
According to Lindemann \[10\% \] law, only \[10\% \] energy is transferred to the next trophic level. If the plants produce \[100\] units of energy, the amount of energy at the level of secondary consumers would be?
A.\[1\] unit
B.\[25\] unit
C.\[50\] unit
D.\[75\] unit
E.\[100\] unit
Answer
492.6k+ views
Hint: A scientist ‘Lindmann’ introduced a law regarding the transfer of energy from one trophic level to the next in the food chain. According to his laws, only the \[10\% \] of the energy produced at a particular trophic level is passed to the next trophic level. The other \[90\% \] is lost in respiration and digestion.
Complete answer:
So, to solve the question related to the energy transfer according to the ‘ Lindmann ’s law’ , always keep in mind the sequence of trophic levels and of which trophic level energy is asked in the question.
So let’s proceed with our given question.
In the question they are saying that, the total energy produced by the plants i.e. the producers are \[100\] unit of energy, so according to Lindemann law, only \[10\% \] of this would be transferred to the next level i.e. to the primary consumers.
So let’s calculate it first:
Hence, energy at the primary consumer level will be-
\[\begin{gathered}
= 10\% {\text{ of }}100 \\
= \dfrac{{10}}{{100}} \times 100 \\
= 10{\text{ unit}} \\
\end{gathered} \]
Now, \[10\% \] of this energy would be transferred to the secondary consumer level. So let’s calculate the total energy present at the secondary consumer level will be:
\[\begin{gathered}
= 10\% {\text{ of }}10 \\
= \dfrac{{10}}{{100}} \times 10 \\
= 1{\text{ unit}} \\
\end{gathered} \]
Hence, their energy present at the secondary consumer level is \[1{\text{ unit}}\].
Therefore, the correct answer is option ‘A ‘i.e. \[1{\text{ unit}}\].
Note:
Always remember to keep in mind the correct order of trophic levels while estimating the total energy at a particular trophic level. The correct order or sequence of trophic level is primary producer \[ \to \] primary consumer \[ \to \] secondary consumer. Here, let’s take an example of a food chain: if the primary producer is a plant, then the primary consumer will be deer and the secondary consumer will be lion.
Complete answer:
So, to solve the question related to the energy transfer according to the ‘ Lindmann ’s law’ , always keep in mind the sequence of trophic levels and of which trophic level energy is asked in the question.
So let’s proceed with our given question.
In the question they are saying that, the total energy produced by the plants i.e. the producers are \[100\] unit of energy, so according to Lindemann law, only \[10\% \] of this would be transferred to the next level i.e. to the primary consumers.
So let’s calculate it first:
Hence, energy at the primary consumer level will be-
\[\begin{gathered}
= 10\% {\text{ of }}100 \\
= \dfrac{{10}}{{100}} \times 100 \\
= 10{\text{ unit}} \\
\end{gathered} \]
Now, \[10\% \] of this energy would be transferred to the secondary consumer level. So let’s calculate the total energy present at the secondary consumer level will be:
\[\begin{gathered}
= 10\% {\text{ of }}10 \\
= \dfrac{{10}}{{100}} \times 10 \\
= 1{\text{ unit}} \\
\end{gathered} \]
Hence, their energy present at the secondary consumer level is \[1{\text{ unit}}\].
Therefore, the correct answer is option ‘A ‘i.e. \[1{\text{ unit}}\].
Note:
Always remember to keep in mind the correct order of trophic levels while estimating the total energy at a particular trophic level. The correct order or sequence of trophic level is primary producer \[ \to \] primary consumer \[ \to \] secondary consumer. Here, let’s take an example of a food chain: if the primary producer is a plant, then the primary consumer will be deer and the secondary consumer will be lion.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

State the laws of reflection of light

Name the metals and nonmetals in the first twenty class 11 chemistry CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

