
According to Franklin, electronation and de-electronation are respectively
A. Oxidation and reduction.
B. Reduction and oxidation.
C. Both oxidations.
D. Both reductions.
Answer
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Hint: Electronation is the process of addition of electrons to a neutral atom to form an anion and De-electronation is the process of removing an electron from a neutral atom to form a cation.
Complete answer:
According to Franklin, the electronation is nothing but the addition of electron and de-electronation is loss of electron.
Gain of electrons is known as reduction, because the no. of electrons present in the atom will be greater than the no. of protons in the atom. Electrons are negatively charged particles so the atom will acquire a negative charge forming it into an anion. Reduction is a decrease in the oxidation state of an atom.
$A + {e^ - } \to {A^ - }$
Loss of electrons is known as oxidation, because the no. of electrons present in the atom will be less than the no. of protons. Protons are positively charged particles so the atom will acquire a positive charge increasing its oxidation number. The atom will be converted into a cation.
$A \to {A^ + } + {e^ - }$
So, now we know that gain of electrons is reduction and loss of electrons is oxidation.
Thus, electronation is known as reduction since it involves gain of electrons. De-electronation is an oxidation because it involves loss of electrons.
Therefore, Option B is correct; reduction and oxidation.
Note: When an atom loses its electron, it gains positive charge and when an atom gains an electron it gains negative charge. An Anion is an ion with a negative charge and a cation is an ion with a positive charge.
Complete answer:
According to Franklin, the electronation is nothing but the addition of electron and de-electronation is loss of electron.
Gain of electrons is known as reduction, because the no. of electrons present in the atom will be greater than the no. of protons in the atom. Electrons are negatively charged particles so the atom will acquire a negative charge forming it into an anion. Reduction is a decrease in the oxidation state of an atom.
$A + {e^ - } \to {A^ - }$
Loss of electrons is known as oxidation, because the no. of electrons present in the atom will be less than the no. of protons. Protons are positively charged particles so the atom will acquire a positive charge increasing its oxidation number. The atom will be converted into a cation.
$A \to {A^ + } + {e^ - }$
So, now we know that gain of electrons is reduction and loss of electrons is oxidation.
Thus, electronation is known as reduction since it involves gain of electrons. De-electronation is an oxidation because it involves loss of electrons.
Therefore, Option B is correct; reduction and oxidation.
Note: When an atom loses its electron, it gains positive charge and when an atom gains an electron it gains negative charge. An Anion is an ion with a negative charge and a cation is an ion with a positive charge.
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