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A village has a population of 6000; 50 liters of water is required per person per day. The village has a water tank measuring$ 60m \times 30m \times 8m$ completely filled with water. For how many days the water of this tank is sufficient.

Answer Verified Verified
Hint: Here we go through by first calculating the total volume of water that the tank has then we will simply divide by the water that the total person of a village consumes water in one day to find out the number of days that the tank is sufficient.

Complete step-by-step answer:
Here in the question it is given that a water tank measuring $60m \times 30m \times 8m$ is completely filled with water.
It means that it is in the shape of a cuboidal tank. So for finding the volume of this cuboidal tank we will apply the formula of volume of cuboid i.e. $V = l \times b \times h$.
So by the required data the volume of the tank is $60m \times 30m \times 8m = 14400{m^3}$
Now we have to first convert this volume in liters because in the question the water consumed per person is given in liters.
And as we know $1{m^3} = 1000liter$.
Now we will convert the total volume of tank in liter i.e. $14400{m^3} = 14400 \times 1000l = 14400000liter$
Now we will calculate the volume of water consumed by the whole village per day.
As in the question it is given that a village has a population of 6000; 50 liters of water is required per person per day.
It means that the total volume of water consumed by whole village per day=$6000 \times 50 = 300000liter$
Now for finding the number of day for sufficiency of tank we will simply divide the total volume of tank by the total volume of water consumed by the whole village i.e. $\dfrac{{14400000l}}{{300000l}} = 48$
Hence Water in the tank is sufficient for 48 days.

Note: Whenever we face such a type of question the key concept for solving the question is first of all always calculate the total volume of a given figure then divide it by the volume which is used to empty out that volume. To get the required number that the question asked.