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**Hint:**In question they are given the production of one day and you have to find the production of $460$ days. For that, you just need to sum up the production of all these days according to one day only, i.e. multiply the production of one day with the number of days.

**Complete step-by-step answer:**

Let’s understand the question first before any calculation. It is given that a factory produces $6348$ tyres in one day. And with this information, we need to find the number of tyres produced in $460$days.

If the factory produces $6348$ tyres in $1$ day

$ \Rightarrow $ For $2$ days, the number of tyres will be: $6348 + 6348 = 2 \times 6348$

$ \Rightarrow $ For $3$ days, the number of tyres will be: $6348 + 6348 + 6348 = 3 \times 6348$

Similarly, for $'n'$ number of days, number of tyres produced will be: $n \times 6348$

Therefore, in $460$ days the number of tyres produced will be: $460 \times 6348 = 2920080$

**Additional Information:**For a better understanding let’s take a case where we need to find production in $10$ daysSo, from the above relation, we can easily solve this case

For $10$ days, number of tyres produced will be: $10 \times 6348 = 63480$

**Note:**Be careful while doing the multiplication in the last step of the calculation. An alternative approach for the process could be when you use the unitary method. This is the same as the above-solved way, but in this method, we need to find the required quantity for unity and then multiply with that factor to get the required result.

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