
A tuning fork of a frequency 480Hz produces 10 beats per second when sounded with a vibrating
(a) 460Hz
(b) 480Hz
(c) 490Hz
(d) 470Hz
Answer
473.4k+ views
Hint: If the length of the string is L, the fundamental harmonic is the one produced by the vibration whose nodes are the two ends of the string, so L is half of the wavelength of the fundamental harmonic. Also beats are defined as the difference between the frequencies.
Complete step by step answer:Given that,
Frequency n = 480 Hz
Number of beat b= 10 b/s
WKT The frequency is directly proportional to the square root of tension.
If a slight increase in tension produces beats per second than before
The frequency of the vibrating string is
$$$$${n_2} = {n_1} + b$…… (1)
${n_2} = 480 + 10$
=490Hz
Similarly,
${n_2} = {n_1} - b$……. (II)
${n_2} = 480 - 10$
=470Hz
Hence, the frequency of the vibrating string will be 490 Hz.
Concluded correct option is C
Note:The beat frequency is when two sound waves with different frequencies come across each other, then their amplitude gets added and subtracted alternatively for a given time period. This leads to the growth of the sound to louder and softer.
Complete step by step answer:Given that,
Frequency n = 480 Hz
Number of beat b= 10 b/s
WKT The frequency is directly proportional to the square root of tension.
If a slight increase in tension produces beats per second than before
The frequency of the vibrating string is
$$$$${n_2} = {n_1} + b$…… (1)
${n_2} = 480 + 10$
=490Hz
Similarly,
${n_2} = {n_1} - b$……. (II)
${n_2} = 480 - 10$
=470Hz
Hence, the frequency of the vibrating string will be 490 Hz.
Concluded correct option is C
Note:The beat frequency is when two sound waves with different frequencies come across each other, then their amplitude gets added and subtracted alternatively for a given time period. This leads to the growth of the sound to louder and softer.
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