
A train is moving at a speed of 220 m/s towards a stationary object, emits a sound of frequency 1000Hz. Some of the sound reaching the object gets reflected back to the train as echo. The frequency of the echo as detected by the driver of the train is (speed off the sound in air is 330 m/s)
A. 4000Hz
B. 5000Hz
C. 3000Hz
D. 3500Hz
Answer
484.5k+ views
Hint: Doppler effect is known as, when the source and observer are moving relative to each other, the frequency observed by the observer ‘ ${f_a}$’ is different from the actual frequency produced by the source ‘ ${f_ \circ }$’. The general formula of doppler effect is given as, $f' = \left( {\dfrac{{v + {v_ \circ }}}{{v - {v_s}}}} \right)f$.
Formula Used: $f' = \left( {\dfrac{{v + {v_ \circ }}}{{v - {v_s}}}} \right)f$
Complete answer:
Frequency is defined as the estimation of the number of times that a repeated event occurs per unit of time. The frequency of wave-like patterns such as the electromagnetic waves i.e. radio waves or light waves, sound waves, electrical signals, or other waves, expresses the number of cycles of the repetitive waveform per second.
According to the concept of doppler effect, when an observer moves towards a stationary source of sound then the apparent frequency heard by the observer increases. So, the apparent frequency heard in this situation is given as,
$f' = \left( {\dfrac{{v + {v_ \circ }}}{{v - {v_s}}}} \right)f$
It is given that the,
Speed of the train = 220 m/s
Speed of the sound in the air = 330 m/s
By applying the doppler effect frequency of the echo which is detected by the driver of the train is given as,
$\eqalign{
& \Rightarrow f' = \left( {\dfrac{{330 + 220}}{{330 - 220}}} \right)1000 \cr
& \Rightarrow f' = 1000\left( {\dfrac{{550}}{{110}}} \right) \cr
& \therefore f' = 5000Hz \cr} $
Thus, the frequency of the echo as detected by the driver of the train is 5000Hz.
Hence, option (B) is the correct answer.
Note:
Students tend to get mistaken that doppler effect is only applicable for sound waves. But, in reality it works with all types of wave forms including light. Some of the applications of doppler effect are:
1) It is used in sirens, radars, and in satellite communications.
2) It is also used for medical purposes such as medical imaging, blood flow measurement.
Formula Used: $f' = \left( {\dfrac{{v + {v_ \circ }}}{{v - {v_s}}}} \right)f$
Complete answer:
Frequency is defined as the estimation of the number of times that a repeated event occurs per unit of time. The frequency of wave-like patterns such as the electromagnetic waves i.e. radio waves or light waves, sound waves, electrical signals, or other waves, expresses the number of cycles of the repetitive waveform per second.
According to the concept of doppler effect, when an observer moves towards a stationary source of sound then the apparent frequency heard by the observer increases. So, the apparent frequency heard in this situation is given as,
$f' = \left( {\dfrac{{v + {v_ \circ }}}{{v - {v_s}}}} \right)f$
It is given that the,
Speed of the train = 220 m/s
Speed of the sound in the air = 330 m/s
By applying the doppler effect frequency of the echo which is detected by the driver of the train is given as,
$\eqalign{
& \Rightarrow f' = \left( {\dfrac{{330 + 220}}{{330 - 220}}} \right)1000 \cr
& \Rightarrow f' = 1000\left( {\dfrac{{550}}{{110}}} \right) \cr
& \therefore f' = 5000Hz \cr} $
Thus, the frequency of the echo as detected by the driver of the train is 5000Hz.
Hence, option (B) is the correct answer.
Note:
Students tend to get mistaken that doppler effect is only applicable for sound waves. But, in reality it works with all types of wave forms including light. Some of the applications of doppler effect are:
1) It is used in sirens, radars, and in satellite communications.
2) It is also used for medical purposes such as medical imaging, blood flow measurement.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

State and prove Bernoullis theorem class 11 physics CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

In which part of the body the blood is purified oxygenation class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells
