A total of 28 handshakes were exchanged at the conclusion of a party. Assuming that each participant was equally polite towards all the others, the number of people present was:
Answer
664.2k+ views
Hint: In this question it is given that the total number of handshakes is 28. So, if we consider that there are ‘n’ number of people. Then the first person shakes hands with (n-1) persons (he can’t shake hands with himself so we have subtracted 1 that n-1). Similarly, the second person shakes hands with (n-2) persons (n-2 because the second person can’t shake hands with himself and the first person is already counted), and so on. At last apply formula, total number of handshakes$\left( {n - 1} \right){\text{ }} + \left( {n - 2} \right){\text{ }} + \ldots .{\text{ }} + 1 = \dfrac{{n(n - 1)}}{2}$.
Complete step-by-step answer: Given,
Total handshakes were exchanged at the conclusion of a party = 28.
We have, total number of handshakes = $\left( {n - 1} \right){\text{ }} + \left( {n - 2} \right){\text{ }} + \ldots .{\text{ }} + 1 = \dfrac{{n(n - 1)}}{2}$
Using the above formula, we get;
$\dfrac{{n(n - 1)}}{2} = 28$
$ \Rightarrow n(n - 1) = 56$
\[ \Rightarrow {n^2} - n - 56 = 0\]
$ \Rightarrow {n^2} - 8n + 7n - 56 = 0$
$ \Rightarrow n(n - 8) + 7(n - 8) = 0$
$ \Rightarrow (n - 8)(n + 7) = 0$
$ \Rightarrow n = 8$ or $ \Rightarrow n = - 7$
Negative number of people is not possible. So, n = -7 is not acceptable.
Therefore, n = 8 is the only acceptable value.
So, the number of people present in the party = 8.
Note: In the above question first person shakes hand with 7 persons, second person shakes hand with 6 persons; similarly, third person shakes hand with 5 persons and so on.
Total handshakes = 7 + 6 + 5 + 4 + 3 + 2 + 1 = 28 Handshakes.
There is an alternative method which can be used in this question by using Combination$^n{C_2} = \dfrac{{n!}}{{2!(n - 2)!}} = \dfrac{{n(n - 1)}}{2}$.
Above equation has a numerical value of 28.
Thus, we get the equation;
$\dfrac{{n(n - 1)}}{2} = 28$
Solving this equation, we get two values, choose the appropriate value.
Subsequent steps are already covered in the main answer. This is the alternative method. We can follow any of the steps for solving this question.
Complete step-by-step answer: Given,
Total handshakes were exchanged at the conclusion of a party = 28.
We have, total number of handshakes = $\left( {n - 1} \right){\text{ }} + \left( {n - 2} \right){\text{ }} + \ldots .{\text{ }} + 1 = \dfrac{{n(n - 1)}}{2}$
Using the above formula, we get;
$\dfrac{{n(n - 1)}}{2} = 28$
$ \Rightarrow n(n - 1) = 56$
\[ \Rightarrow {n^2} - n - 56 = 0\]
$ \Rightarrow {n^2} - 8n + 7n - 56 = 0$
$ \Rightarrow n(n - 8) + 7(n - 8) = 0$
$ \Rightarrow (n - 8)(n + 7) = 0$
$ \Rightarrow n = 8$ or $ \Rightarrow n = - 7$
Negative number of people is not possible. So, n = -7 is not acceptable.
Therefore, n = 8 is the only acceptable value.
So, the number of people present in the party = 8.
Note: In the above question first person shakes hand with 7 persons, second person shakes hand with 6 persons; similarly, third person shakes hand with 5 persons and so on.
Total handshakes = 7 + 6 + 5 + 4 + 3 + 2 + 1 = 28 Handshakes.
There is an alternative method which can be used in this question by using Combination$^n{C_2} = \dfrac{{n!}}{{2!(n - 2)!}} = \dfrac{{n(n - 1)}}{2}$.
Above equation has a numerical value of 28.
Thus, we get the equation;
$\dfrac{{n(n - 1)}}{2} = 28$
Solving this equation, we get two values, choose the appropriate value.
Subsequent steps are already covered in the main answer. This is the alternative method. We can follow any of the steps for solving this question.
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

