
When a thin mica sheet is placed between the plates of a condenser then the amount of charge, so compared to its previous value, on its plates will become:
A. unchanged
B. zero
C. less
D. more
Answer
579.3k+ views
Hint: We have already studied about the conservation of charge in the properties of charge. By applying the same concept to the above question we can easily come across with the solution.
Complete step by step answer:
Conservation of charge requires that equal-magnitude charges be created on the plates of the individual capacitors, since charge is only being separated in these originally neutral devices.
Charges on the plate of capacitors will not change, therefore charge is conserved.
Hence the correct option is A.
Note:
When the capacitors are in series this is not that case. The charge in the wire between the first and second capacitors must remain in that segment (the electrons can only move through a conductor and the gaps are dielectrics). This means that +Q is on one capacitor (one side of the wire segment) then −Q must be on the other capacitor (the other side of the wire). Another way to put it is that there must be charge conservation on an isolated conductor.
Complete step by step answer:
Conservation of charge requires that equal-magnitude charges be created on the plates of the individual capacitors, since charge is only being separated in these originally neutral devices.
Charges on the plate of capacitors will not change, therefore charge is conserved.
Hence the correct option is A.
Note:
When the capacitors are in series this is not that case. The charge in the wire between the first and second capacitors must remain in that segment (the electrons can only move through a conductor and the gaps are dielectrics). This means that +Q is on one capacitor (one side of the wire segment) then −Q must be on the other capacitor (the other side of the wire). Another way to put it is that there must be charge conservation on an isolated conductor.
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