
A tablet of Vitamin C is analyzed for its ascorbic acid content. One tablet reacts exactly with 20 ml of 0.1 Normal NaOH Solution. The equivalent weight of Ascorbic acid is 176. The tablet Contains \[\_\_\_\_\_\_\_mg\] of ascorbic Acid
A. 0.352
B. 3.52
C. 35.2
D. 352
Answer
547.2k+ views
Hint:For any reaction, we can equate the number of equivalences for reactants and products. By using a number of equivalences of a substance \[{{n}_{eq}}\], we calculate the values and substitute and find out the weight of the ascorbic acid in milligrams.
Complete step by step answer:
For any reaction, we can equate the number of equivalences for reactants and products. Let us calculate the number of equivalences of a substance by using the formula \[{{n}_{eq}}=n.{{n}_{f}}=N.V\].
Where in the given equation, n indicated number of moles of the given substance
\[{{n}_{f}}\] is the n-factor ( which is nothing but the value obtained after dividing molar weight ( represented as capital m ( M ) ) by Equivalent weight( represented as capital e ( E ) ) of the given substance )
N is normality of the given substance and V is volume of the given substance in liters.
Now let us find the \[{{n}_{eq}}\] of the ascorbic acid
\[{{n}_{eq}}\] of the ascorbic acid\[=n.{{n}_{f}}=n.\dfrac{M}{V}=n.\dfrac{176}{176}=n\]
Now let us find out the \[{{n}_{eq}}\] of \[NaOH\]
\[{{n}_{eq}}\] of \[NaOH\]\[=N.V=(0.1)\left( \dfrac{20}{1000} \right)=0.002\]
Now let us equate but the values we get are the number of moles of ascorbic acid as 0.002.
\[\Rightarrow n=0.002\] moles of ascorbic acid.
Now let us calculate the weight of ascorbic acid by multiplying the number of moles with molar weight we get
Weight of ascorbic acid \[=n.M=0.002\times 176=0.352\]
So we got a weight of ascorbic acid equal to 0.352 grams.
Let us convert it into milligrams, we get
Weight of ascorbic acid \[=352mg\]
\[\therefore \] Option D is correct.
Note:
Vitamin C is a vitamin found in various foods and sold as a dietary supplement. It is used to prevent and treat scurvy. Vitamin C is an essential nutrient involved in the repair of tissue and the enzymatic production of certain neurotransmitters.
Complete step by step answer:
For any reaction, we can equate the number of equivalences for reactants and products. Let us calculate the number of equivalences of a substance by using the formula \[{{n}_{eq}}=n.{{n}_{f}}=N.V\].
Where in the given equation, n indicated number of moles of the given substance
\[{{n}_{f}}\] is the n-factor ( which is nothing but the value obtained after dividing molar weight ( represented as capital m ( M ) ) by Equivalent weight( represented as capital e ( E ) ) of the given substance )
N is normality of the given substance and V is volume of the given substance in liters.
Now let us find the \[{{n}_{eq}}\] of the ascorbic acid
\[{{n}_{eq}}\] of the ascorbic acid\[=n.{{n}_{f}}=n.\dfrac{M}{V}=n.\dfrac{176}{176}=n\]
Now let us find out the \[{{n}_{eq}}\] of \[NaOH\]
\[{{n}_{eq}}\] of \[NaOH\]\[=N.V=(0.1)\left( \dfrac{20}{1000} \right)=0.002\]
Now let us equate but the values we get are the number of moles of ascorbic acid as 0.002.
\[\Rightarrow n=0.002\] moles of ascorbic acid.
Now let us calculate the weight of ascorbic acid by multiplying the number of moles with molar weight we get
Weight of ascorbic acid \[=n.M=0.002\times 176=0.352\]
So we got a weight of ascorbic acid equal to 0.352 grams.
Let us convert it into milligrams, we get
Weight of ascorbic acid \[=352mg\]
\[\therefore \] Option D is correct.
Note:
Vitamin C is a vitamin found in various foods and sold as a dietary supplement. It is used to prevent and treat scurvy. Vitamin C is an essential nutrient involved in the repair of tissue and the enzymatic production of certain neurotransmitters.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

