
A tablet of Vitamin C is analyzed for its ascorbic acid content. One tablet reacts exactly with 20 ml of 0.1 Normal NaOH Solution. The equivalent weight of Ascorbic acid is 176. The tablet Contains \[\_\_\_\_\_\_\_mg\] of ascorbic Acid
A. 0.352
B. 3.52
C. 35.2
D. 352
Answer
550.5k+ views
Hint:For any reaction, we can equate the number of equivalences for reactants and products. By using a number of equivalences of a substance \[{{n}_{eq}}\], we calculate the values and substitute and find out the weight of the ascorbic acid in milligrams.
Complete step by step answer:
For any reaction, we can equate the number of equivalences for reactants and products. Let us calculate the number of equivalences of a substance by using the formula \[{{n}_{eq}}=n.{{n}_{f}}=N.V\].
Where in the given equation, n indicated number of moles of the given substance
\[{{n}_{f}}\] is the n-factor ( which is nothing but the value obtained after dividing molar weight ( represented as capital m ( M ) ) by Equivalent weight( represented as capital e ( E ) ) of the given substance )
N is normality of the given substance and V is volume of the given substance in liters.
Now let us find the \[{{n}_{eq}}\] of the ascorbic acid
\[{{n}_{eq}}\] of the ascorbic acid\[=n.{{n}_{f}}=n.\dfrac{M}{V}=n.\dfrac{176}{176}=n\]
Now let us find out the \[{{n}_{eq}}\] of \[NaOH\]
\[{{n}_{eq}}\] of \[NaOH\]\[=N.V=(0.1)\left( \dfrac{20}{1000} \right)=0.002\]
Now let us equate but the values we get are the number of moles of ascorbic acid as 0.002.
\[\Rightarrow n=0.002\] moles of ascorbic acid.
Now let us calculate the weight of ascorbic acid by multiplying the number of moles with molar weight we get
Weight of ascorbic acid \[=n.M=0.002\times 176=0.352\]
So we got a weight of ascorbic acid equal to 0.352 grams.
Let us convert it into milligrams, we get
Weight of ascorbic acid \[=352mg\]
\[\therefore \] Option D is correct.
Note:
Vitamin C is a vitamin found in various foods and sold as a dietary supplement. It is used to prevent and treat scurvy. Vitamin C is an essential nutrient involved in the repair of tissue and the enzymatic production of certain neurotransmitters.
Complete step by step answer:
For any reaction, we can equate the number of equivalences for reactants and products. Let us calculate the number of equivalences of a substance by using the formula \[{{n}_{eq}}=n.{{n}_{f}}=N.V\].
Where in the given equation, n indicated number of moles of the given substance
\[{{n}_{f}}\] is the n-factor ( which is nothing but the value obtained after dividing molar weight ( represented as capital m ( M ) ) by Equivalent weight( represented as capital e ( E ) ) of the given substance )
N is normality of the given substance and V is volume of the given substance in liters.
Now let us find the \[{{n}_{eq}}\] of the ascorbic acid
\[{{n}_{eq}}\] of the ascorbic acid\[=n.{{n}_{f}}=n.\dfrac{M}{V}=n.\dfrac{176}{176}=n\]
Now let us find out the \[{{n}_{eq}}\] of \[NaOH\]
\[{{n}_{eq}}\] of \[NaOH\]\[=N.V=(0.1)\left( \dfrac{20}{1000} \right)=0.002\]
Now let us equate but the values we get are the number of moles of ascorbic acid as 0.002.
\[\Rightarrow n=0.002\] moles of ascorbic acid.
Now let us calculate the weight of ascorbic acid by multiplying the number of moles with molar weight we get
Weight of ascorbic acid \[=n.M=0.002\times 176=0.352\]
So we got a weight of ascorbic acid equal to 0.352 grams.
Let us convert it into milligrams, we get
Weight of ascorbic acid \[=352mg\]
\[\therefore \] Option D is correct.
Note:
Vitamin C is a vitamin found in various foods and sold as a dietary supplement. It is used to prevent and treat scurvy. Vitamin C is an essential nutrient involved in the repair of tissue and the enzymatic production of certain neurotransmitters.
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