Question

A table cover \[5m \times 3m\], is spread on a meeting table. If \[25{\text{ }}cm\] of the table cover is hanging all around the table, find the area of the table top.

Answer 1

Hint- To find the necessary area, we must simply use the rectangle area given by multiplying length and breadth so that we can first measure the length and breadth with the aid of the given statement and finally, by putting these values into formula, we must obtain the required response.

Complete step-by-step answer:
Given statement is table cover \[5m \times 3m\], is spread on a meeting table and \[25{\text{ }}cm\] of the table cover is hanging all around the table
Length of table cover is \[5m\]=500cm
Extra length of cover hanging all around the table =25cm
So , the length of the table top \[ = {\text{ }}500{\text{ }} - {\text{ }}25{\text{ }} = {\text{ }}475{\text{ }}cm\]
Breadth of table cover is \[3m\]=300cm
Extra breadth of cover hanging all around the table=25cm
So , the breadth of the table top = \[ = {\text{ }}300{\text{ }} - {\text{ }}25{\text{ }} = {\text{ }}275{\text{ }}cm\]
As we know that the area of rectangle = Length \[ \times \] Breadth
Area of table top = Length of the table top \[ \times \]
breadth of the table top
\[ = (475 \times 275){m^2} = 130,625{cm^2}\]

Hence the required area of table top =\[13.062{m^2}\]


Note- Area of the rectangle is given by the multiplication of its length and breath if the length of the rectangle is \[L\] and the breath is \[B\] then the area of the rectangle would be \[A = L \times B\].