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How can a system of equations have no solution ?

Answer
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Hint: Here in this question, we explain how a system of equations a1x+b1y+c1=0 and a2x+b2y+c2=0 have no solution. If (a1a2)=(b1b2)(c1c2) then there will be no solution. This type of equation is called an inconsistent pair of linear equations. If we plot the graph, the lines will be parallel.

Complete step-by-step answer:
An equation of the form ax+by+c=0 where a , b , c R , a0 and b0 is a linear equation in two variables. While considering the system of linear equations, we can find the number of solutions by comparing the coefficients of the equations. Also, we can find whether the system of equations has no solution or infinitely many solutions by graphical method.
Let us consider the pair of linear equations in two variables x and y.
 a1x+b1y+c1=0
 a2x+b2y+c2=0
Here a1 , b1 , c1 , a2 , b2 , c2 are real numbers. Note that a12+b120 , a22+b220
If (a1a2)=(b1b2)(c1c2) then there will be no solution. This type of equation is called an inconsistent pair of linear equations. If we plot the graph, the lines will be parallel.
Consider an example
 y=4x+11
 y=4x+5
Here these system of linear equations satisfied the condition (a1a2)=(b1b2)(c1c2) , both the lines have same slope 4 which means lines are parallel never intersect. That being said, there is no solution to this problem.

Note: While solving the system of equations sometimes we get the value of an unknown variable. By the equation we can plot the graph also, if they are parallel to each other then we will not be able to find the solution for the system of equations. Hence the above example represents that the system of equations has no solutions.