
A swimming pool of length$ = 25m$, breadth$ = 15m$ and height$ = 2m$ is three fourths full of water. Find the volume of water in the pool.
Answer
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Hint: The given question is from mensuration topic. Menstruation involves the study of area, perimeter and volume of various shapes like cylinder, cuboid, cube, etc. In such questions, we first find the volume of the whole swimming pool and then find the volume of the pool that is filled with water. Hence, we can find the volume of water held in the pool in this easy way.
Complete step by step solution:
In the question, we are required to find the volume of water present in the pool. So, we first find the volume of the entire pool.
We know that the volume of cuboid is given by $Volume\,of\,Cuboid = \left( {length} \right) \times \left( {breadth} \right) \times \left( {height} \right)$. So, Volume of the swimming pool $ = \left( {25m} \right) \times \left( {15m} \right) \times \left( {2m} \right)$
$ \Rightarrow $ Volume of the swimming pool $ = 750{m^3}$
So, the volume of the entire swimming pool is $750{m^3}$.
Now, we are given that only three fourths of the swimming pool is filled with water.
Hence, the volume of water present in swimming pool$ = \left( {\dfrac{3}{4}} \right) \times 750{m^3} = 562.5{m^3}$
Therefore, the volume of water present in the swimming pool is $562.5{m^3}$.
Note: One should have knowledge about fractions and mensuration for attempting such questions. Volume of a cuboid should be known. Also, care should be taken while doing calculations and unit conversion, if required.
Complete step by step solution:
In the question, we are required to find the volume of water present in the pool. So, we first find the volume of the entire pool.
We know that the volume of cuboid is given by $Volume\,of\,Cuboid = \left( {length} \right) \times \left( {breadth} \right) \times \left( {height} \right)$. So, Volume of the swimming pool $ = \left( {25m} \right) \times \left( {15m} \right) \times \left( {2m} \right)$
$ \Rightarrow $ Volume of the swimming pool $ = 750{m^3}$
So, the volume of the entire swimming pool is $750{m^3}$.
Now, we are given that only three fourths of the swimming pool is filled with water.
Hence, the volume of water present in swimming pool$ = \left( {\dfrac{3}{4}} \right) \times 750{m^3} = 562.5{m^3}$
Therefore, the volume of water present in the swimming pool is $562.5{m^3}$.
Note: One should have knowledge about fractions and mensuration for attempting such questions. Volume of a cuboid should be known. Also, care should be taken while doing calculations and unit conversion, if required.
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