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To start with the solution we let the side length of the inner square be a meter.

Now we will draw the diagram of the situation given in the question.

Now let us move to the area of the area of the road, for which side length is 6m more than that of the inner square, as 3m wide from each of the inner square. So, the side length of the outer square is (a+6) m. We also need to subtract the area of the inner square from the area of the outer square to get the area of the road. We know that the area of the square is equal to the square of its side length.

$\text{Area of the road}=\text{Area of the outer square}-\text{Area of the inner square}\text{. }$

$\Rightarrow \text{Area of the road}={{\left( a+6 \right)}^{2}}-{{a}^{2}}\text{. }$

Also, it is given that the area of the road is 1764 sq meters.

\[1764={{\left( a+6 \right)}^{2}}-{{a}^{2}}\text{. }\]

Now we will use the formula ${{a}^{2}}-{{b}^{2}}=\left( a+b \right)\left( a-b \right)$ . On doing so, we get

\[1764=\left( a+6-a \right)\left( a+6+a \right)\text{ }\]

\[\Rightarrow 1764=6\left( 2a+6 \right)\text{ }\]

\[\Rightarrow 294=2a+6\]

\[\Rightarrow 2a=288\]

\[\Rightarrow a=144meters\]

Therefore, the side length of the outer square is a+6=144+6=150 meters.

Now we know that the perimeter of a square is 4 times its side length. So, the perimeter along the outer edges is $4\times 150=600m$ .

Therefore, the answer to the above question is 600m.

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