
A spring when stretched by $ 2\;mm\; $ its potential energy becomes $ 4\;J $ . If it is stretched by $ 10\;mm $ , its potential energy is equal to
A) $ 4{\text{ }}J $
B) $ 54{\text{ }}J $
C) $ 415{\text{ }}J $
D) $ 100{\text{ }}J $
Answer
485.1k+ views
Hint: According to the question when a spring is stretched by $ 2\;mm\; $ its potential energy becomes $ 4\;J $ . If it is stretched by $ 10\;mm $ , then we have to calculate its potential energy now. Here the formula which will be used to solve this question is $ U = \dfrac{1}{2}k{x^2} $ , where k is the spring constant.
Complete step by step answer:
A spring is an elastic object that stores mechanical energy. Springs are typically made of spring steel. There are many spring designs. In everyday use, the term often refers to coil springs. In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Elastic potential energy is Potential energy stored as a result of deformation of an elastic object, such as the stretching of a spring. It is equal to the work done to stretch the spring, which depends upon the spring constant k as well as the distance stretched. According to Hooke's law the force required to stretch the spring will be directly proportional to the amount of stretch.
Since the force has the form, $ F = - kx $
Then the work done to stretch the spring a distance x is $ Work = \Delta PE = \dfrac{1}{2}k{x^2} $
Let extension produced in the spring be x initially in the stretched condition. Spring will have potential energy, $ U = \dfrac{1}{2}k{x^2} $ , where k is the spring constant.
Further we know that, $ {x_1} = 2cm $ and $ {x_2} = 10cm $
Now if x becomes 5 times then energy will become 25 times, i.e., $ 4 \times 25 = 100J $ ( as there is square relation ).
Hence the final answer is D) $ 100J $ .
Note:
Be careful while applying the conditions given in the question. While solving the question, keep in mind the formula of potential energy. Calculation mistakes are possible, so try to avoid them. Another thing to keep in mind is that if x becomes $ 5 $ times then energy will become $ 25 $ times as there is a square relation.
Complete step by step answer:
A spring is an elastic object that stores mechanical energy. Springs are typically made of spring steel. There are many spring designs. In everyday use, the term often refers to coil springs. In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Elastic potential energy is Potential energy stored as a result of deformation of an elastic object, such as the stretching of a spring. It is equal to the work done to stretch the spring, which depends upon the spring constant k as well as the distance stretched. According to Hooke's law the force required to stretch the spring will be directly proportional to the amount of stretch.
Since the force has the form, $ F = - kx $
Then the work done to stretch the spring a distance x is $ Work = \Delta PE = \dfrac{1}{2}k{x^2} $
Let extension produced in the spring be x initially in the stretched condition. Spring will have potential energy, $ U = \dfrac{1}{2}k{x^2} $ , where k is the spring constant.
Further we know that, $ {x_1} = 2cm $ and $ {x_2} = 10cm $
Now if x becomes 5 times then energy will become 25 times, i.e., $ 4 \times 25 = 100J $ ( as there is square relation ).
Hence the final answer is D) $ 100J $ .
Note:
Be careful while applying the conditions given in the question. While solving the question, keep in mind the formula of potential energy. Calculation mistakes are possible, so try to avoid them. Another thing to keep in mind is that if x becomes $ 5 $ times then energy will become $ 25 $ times as there is a square relation.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

