
A spherical ball contracts in volume by 0.01 % when subjected to a normal uniform pressure of 100 atm. The Bulk modulus of its material is
(A). \[1.01 \times {10^{11}}N{m^{ - 2}}\]
(B). \[1.01 \times {10^{12}}N{m^{ - 2}}\]
(C). \[1.01 \times {10^{10}}N{m^{ - 2}}\]
(D). \[1.01 \times {10^{13}}N{m^{ - 2}}\]
Answer
529.9k+ views
Hint: Bulk modulus is a numerical constant that defines solid or fluid elastic properties when it is under pressure on all surfaces. The pressure applied increases the volume of a substance and when the pressure is removed returns to its original volume.
Formula used: \[{\text{B = }}\dfrac{{\vartriangle {\text{P}}}}{{(\dfrac{{\vartriangle {\text{v}}}}{{\text{v}}}{\text{)}}}}\]Where,
B = Bulk modulus
\[\vartriangle P\] = Change of the pressure or force applied on the material per unit area
\[\vartriangle V\]= Change of material volume due to compression
V = Initial material volume in English system units, and \[N/{m^2}\]in metric scale.
Complete step-by-step solution -
Since the number of spherical contracts is 0.01%
\[ \Rightarrow \dfrac{{\vartriangle v}}{v} = \dfrac{{0.01}}{{100}}\]
So Bulk modulus ‘B’ is given by
\[{\text{B = }}\dfrac{{\vartriangle {\text{P}}}}{{(\dfrac{{\vartriangle {\text{v}}}}{{\text{v}}}{\text{)}}}}\]
\[ \Rightarrow {\text{B = }}\dfrac{{100 \times 1.01 \times {{10}^5}}}{{\dfrac{{0.01}}{{100}}}}\]
\[\because \;{\text{1 atm = 1}}{\text{.01 }} \times {\text{ 1}}{{\text{0}}^5}N/{m^2}\]
\[ \Rightarrow B = 1.01 \times {10^{11}}N{m^{ - 2}}\]
Hence option A is the correct answer.
Additional information-
Bulk modulus is used to calculate the incompressibility of a solid. Besides, the higher value of K for a substance, the more incompressible its existence is. For example, for steel, the value of K is \[1.6 \times {10^{11}}N/{m^2}\]and the value of K for glass is \[4 \times {10^{10}}N/{m^2}\]. K for steel, here, is more than three times the glass value of K. Which means more compressible glass than steel.
The standard atmosphere (symbol: atm) is a pressure unit specified as 101325 Pa (1.01325 bar). It is commonly used as a reference or standard pressure. At sea level, it is nearly equal to the air pressure.
Note: Bulk elasticity modulus is the one measure of solids' mechanical properties. Certain elastic modules include module Young and module Shear. In any case, a material's bulk elastic properties are used to determine how much it can compress under a specified amount of outer pressure. Here the ratio of the change in pressure to the compression of the fractional volume is important to find and remember.
Formula used: \[{\text{B = }}\dfrac{{\vartriangle {\text{P}}}}{{(\dfrac{{\vartriangle {\text{v}}}}{{\text{v}}}{\text{)}}}}\]Where,
B = Bulk modulus
\[\vartriangle P\] = Change of the pressure or force applied on the material per unit area
\[\vartriangle V\]= Change of material volume due to compression
V = Initial material volume in English system units, and \[N/{m^2}\]in metric scale.
Complete step-by-step solution -
Since the number of spherical contracts is 0.01%
\[ \Rightarrow \dfrac{{\vartriangle v}}{v} = \dfrac{{0.01}}{{100}}\]
So Bulk modulus ‘B’ is given by
\[{\text{B = }}\dfrac{{\vartriangle {\text{P}}}}{{(\dfrac{{\vartriangle {\text{v}}}}{{\text{v}}}{\text{)}}}}\]
\[ \Rightarrow {\text{B = }}\dfrac{{100 \times 1.01 \times {{10}^5}}}{{\dfrac{{0.01}}{{100}}}}\]
\[\because \;{\text{1 atm = 1}}{\text{.01 }} \times {\text{ 1}}{{\text{0}}^5}N/{m^2}\]
\[ \Rightarrow B = 1.01 \times {10^{11}}N{m^{ - 2}}\]
Hence option A is the correct answer.
Additional information-
Bulk modulus is used to calculate the incompressibility of a solid. Besides, the higher value of K for a substance, the more incompressible its existence is. For example, for steel, the value of K is \[1.6 \times {10^{11}}N/{m^2}\]and the value of K for glass is \[4 \times {10^{10}}N/{m^2}\]. K for steel, here, is more than three times the glass value of K. Which means more compressible glass than steel.
The standard atmosphere (symbol: atm) is a pressure unit specified as 101325 Pa (1.01325 bar). It is commonly used as a reference or standard pressure. At sea level, it is nearly equal to the air pressure.
Note: Bulk elasticity modulus is the one measure of solids' mechanical properties. Certain elastic modules include module Young and module Shear. In any case, a material's bulk elastic properties are used to determine how much it can compress under a specified amount of outer pressure. Here the ratio of the change in pressure to the compression of the fractional volume is important to find and remember.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

