
A source of sound is travelling with a velocity 40 $km/hr$ towards an observer and emits sound of frequency 2000 Hz. If velocity of sound is 1220 km/hr, then what is the apparent frequency heard by an observer?
$\text{A}\text{. 2210 Hz}$
$\text{B}\text{. 1920 Hz}$
$\text{C}\text{. 2068 Hz}$
$\text{D}\text{. 2086 Hz}$
Answer
566.1k+ views
Hint: When a source of wave is moving with respect to an observer, there is an apparent change in frequency of the wave depending on the direction of movement of the source. This effect is known as Doppler’s effect.
The shift in frequency can be calculated using Doppler’s shift formula.
Formula Used:
$f=\left( \dfrac{v\pm {{v}_{o}}}{v\pm {{v}_{s}}} \right){{f}_{0}}$
Complete answer:
Doppler effect, also known as Doppler shift, is the phenomenon that is observed when the source of a wave is moving with respect to an observer.
A train approaching you with blasting its horn is a common example of the Doppler Effect.
If ${{f}_{0}}$ and v are the frequency and velocity of the wave produced by the source moving with velocity ${{v}_{s}}$ and ${{v}_{o}}$is the velocity of the observer, then the apparent frequency is given by
$f=\left( \dfrac{v\pm {{v}_{o}}}{v\pm {{v}_{s}}} \right){{f}_{0}}$
${{v}_{r}}$ is taken positive if the observer moves towards the source and negative if it moves away from the source
${{v}_{s}}$ is positive if the source moves away from the observer and negative if it moves in the opposite direction.
In this question, the source of sound moves towards an observer with velocity, ${{v}_{s}}=-40km/hr$.
Observer is stationary, ${{v}_{o}}=0km/hr$
Velocity of the sound is $v=1220km/hr$
Frequency of the sound is ${{f}_{0}}=2000Hz$
We substitute these values in Doppler shift formula and get
$f=\left( \dfrac{1220+0}{1220-40} \right)(2000)=\dfrac{1220}{1180}\times 2000$
$\Rightarrow f=2068Hz$
Hence, option C is correct.
Note:
If the motion of the source of the wave relative to the observer is towards it then the Doppler shift is positive i.e. apparent frequency is higher than actual frequency. If the source moves in the opposite direction with respect to the observer, there is a downward shift in observed frequency.
It must be noted here that Doppler shift is not due to real shift in frequency of the source.
The shift in frequency can be calculated using Doppler’s shift formula.
Formula Used:
$f=\left( \dfrac{v\pm {{v}_{o}}}{v\pm {{v}_{s}}} \right){{f}_{0}}$
Complete answer:
Doppler effect, also known as Doppler shift, is the phenomenon that is observed when the source of a wave is moving with respect to an observer.
A train approaching you with blasting its horn is a common example of the Doppler Effect.
If ${{f}_{0}}$ and v are the frequency and velocity of the wave produced by the source moving with velocity ${{v}_{s}}$ and ${{v}_{o}}$is the velocity of the observer, then the apparent frequency is given by
$f=\left( \dfrac{v\pm {{v}_{o}}}{v\pm {{v}_{s}}} \right){{f}_{0}}$
${{v}_{r}}$ is taken positive if the observer moves towards the source and negative if it moves away from the source
${{v}_{s}}$ is positive if the source moves away from the observer and negative if it moves in the opposite direction.
In this question, the source of sound moves towards an observer with velocity, ${{v}_{s}}=-40km/hr$.
Observer is stationary, ${{v}_{o}}=0km/hr$
Velocity of the sound is $v=1220km/hr$
Frequency of the sound is ${{f}_{0}}=2000Hz$
We substitute these values in Doppler shift formula and get
$f=\left( \dfrac{1220+0}{1220-40} \right)(2000)=\dfrac{1220}{1180}\times 2000$
$\Rightarrow f=2068Hz$
Hence, option C is correct.
Note:
If the motion of the source of the wave relative to the observer is towards it then the Doppler shift is positive i.e. apparent frequency is higher than actual frequency. If the source moves in the opposite direction with respect to the observer, there is a downward shift in observed frequency.
It must be noted here that Doppler shift is not due to real shift in frequency of the source.
Recently Updated Pages
Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 7 Maths: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 6 Maths: Engaging Questions & Answers for Success

Class 6 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

