Question

A solution contains ${ 2.80 }$ moles of acetone ${ CH }_{ 3 }{ COCH }_{ 3 }$ and ${ 8.20 }$ moles of ${ CHCl }_{ 3 }$. Calculate the mole fraction of acetone. (Give answer in 110X).

Answer 1

Hint: Mole fraction of any component is the number of moles of that component by the total number of moles of the solution. Mole fraction of a component in a mixture or solution = no. of moles of the component / total moles of the mixture or solution.

Complete step-by-step answer:

It is given that:
Number of moles of acetone = ${ 2.80mol }$
Number of moles of chloroform = ${ 8.20mol }$
By using the given formula, we get
Mole fraction ${ x }_{ 1 }{ =n }_{ 1 }\div { n }_{ 1 }{ +n }_{ 2 }$
where, ${ x }_{ 1 }$ = mole fraction of acetone
${ n }_{ 1 }$ = number of moles of acetone
${ n }_{ 2 }$ = number of moles of chloroform
Now, put the values in the above formula, we get
${ x }_{ 1 }{ =2.8\div 2.80+8.2 }$
${ x }_{ 1 }{ =2.8\div 11 }$
${ x }_{ 1 }{ =0.255 }$
Hence, the mole fraction of acetone ${ 0.255 }$.

Additional Information:
Acetone is an organic compound, which is a volatile substance (evaporates at room temperature). It is used in nail polish remover.
Acetone is miscible with water and serves as an important solvent in its own right, typically for cleaning purposes in the laboratory.
Chloroform or trichloromethane is an organic compound that has many industrial devices but is mainly associated with criminals for using chloroform to make a person unconscious.

Note: The possibility to make a mistake is that you have to find the number of moles of component ${ 1 }$ by using ${ x }_{ 1 }{ =n }_{ 1 }\div { n }_{ 1 }{ +n }_{ 2 }$ and not component ${ 2 }$ ${ x }_{ 2 }{ =n }_{ 2 }\div { n }_{ 1 }{ +n }_{ 2 }$.