
A solution contains 25% water, 50% ethanoic acid, and 25% ethanol by mass. Compute the mole fraction of each.
Answer
580.8k+ views
Hint: Mole fraction of the component is calculated by dividing the mole of the component to the total moles of all the components in the solution. The moles of the component is calculated by dividing the given mass of the component to the molecular mass of it.
Complete answer:
Mole fraction of any component in the solution is equal to the number of moles of that component divided by the total number of moles of all the components. For a solution containing ${{n}_{2}}$ moles of the solute dissolved in ${{n}_{1}}$ moles of the solvent.
Mole fraction of solute = ${{x}_{2}}=\dfrac{{{n}_{2}}}{{{n}_{2}}+{{n}_{1}}}$
Mole fraction of solvent = ${{x}_{1}}=\dfrac{{{n}_{1}}}{{{n}_{2}}+{{n}_{1}}}$
The sum of the mole fraction of the components is equal to 1.
The moles of the component is calculated by dividing the given mass of the component to the molecular mass of it.
$moles=\dfrac{given\text{ }mass}{molecular\text{ }mass}$
So, in the question the solution contains 25% water, 50% ethanoic acid, and 25% ethanol by mass.
25% of water means 25 g of water is present in 100 g of solution.
50% of ethanoic acid means 50 g of ethanoic acid is present in 100 g of solution.
25% of ethanol means 25 g of ethanol is present in 100 g of solution.
The molecular mass of water = $18g/mol$
The molecular mass of ethanoic acid = $60g/mol$
The molecular mass of ethanol = $46g/mol$
Number of moles of water = $\dfrac{25}{18}=1.4$
Number of moles of ethanoic acid = $\dfrac{50}{60}=0.8$
Number of moles of ethanol = $\dfrac{25}{46}=0.54$
So, the total number of moles of all components in the solution = 1.4+0.54+0.8 = 2.74
So, we have the moles of each component and total moles of the solution, therefore,
Mole fraction of water = $\dfrac{1.4}{2.74}=0.51$
Mole fraction of ethanoic acid =$\dfrac{0.8}{2.74}=0.291$
Mole fraction of ethanol = $\dfrac{0.54}{2.74}=0.197$
Hence the mole fraction of water is 0.51, ethanoic acid is 0.291, and ethanol is 0.197.
Note:
Mole fraction is a dimensionless quantity because we are dividing the moles with moles. When the percentage of the components is converted into mass, 100 g of the solution is taken for the easy calculation.
Complete answer:
Mole fraction of any component in the solution is equal to the number of moles of that component divided by the total number of moles of all the components. For a solution containing ${{n}_{2}}$ moles of the solute dissolved in ${{n}_{1}}$ moles of the solvent.
Mole fraction of solute = ${{x}_{2}}=\dfrac{{{n}_{2}}}{{{n}_{2}}+{{n}_{1}}}$
Mole fraction of solvent = ${{x}_{1}}=\dfrac{{{n}_{1}}}{{{n}_{2}}+{{n}_{1}}}$
The sum of the mole fraction of the components is equal to 1.
The moles of the component is calculated by dividing the given mass of the component to the molecular mass of it.
$moles=\dfrac{given\text{ }mass}{molecular\text{ }mass}$
So, in the question the solution contains 25% water, 50% ethanoic acid, and 25% ethanol by mass.
25% of water means 25 g of water is present in 100 g of solution.
50% of ethanoic acid means 50 g of ethanoic acid is present in 100 g of solution.
25% of ethanol means 25 g of ethanol is present in 100 g of solution.
The molecular mass of water = $18g/mol$
The molecular mass of ethanoic acid = $60g/mol$
The molecular mass of ethanol = $46g/mol$
Number of moles of water = $\dfrac{25}{18}=1.4$
Number of moles of ethanoic acid = $\dfrac{50}{60}=0.8$
Number of moles of ethanol = $\dfrac{25}{46}=0.54$
So, the total number of moles of all components in the solution = 1.4+0.54+0.8 = 2.74
So, we have the moles of each component and total moles of the solution, therefore,
Mole fraction of water = $\dfrac{1.4}{2.74}=0.51$
Mole fraction of ethanoic acid =$\dfrac{0.8}{2.74}=0.291$
Mole fraction of ethanol = $\dfrac{0.54}{2.74}=0.197$
Hence the mole fraction of water is 0.51, ethanoic acid is 0.291, and ethanol is 0.197.
Note:
Mole fraction is a dimensionless quantity because we are dividing the moles with moles. When the percentage of the components is converted into mass, 100 g of the solution is taken for the easy calculation.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

