
A sold a watch to B at 20% gain, and B sold it to C at a loss of 10%. If C bought the watch for Rs.216, at what price did A purchase it?
A. Rs100.
B. Rs150.
C. Rs200.
D. Rs250.
Answer
585.3k+ views
Hint: Firstly we have to assume the CP of A and then calculate the gain with the CP by this formula \[SP=\left[ \dfrac{\left( 100+gain\% \right)}{100}\times CP \right]\]. Now we get the CP of B. Then a similar way we have to find the CP of C by using this formula \[SP=\left[ \dfrac{\left( 100-loss\% \right)}{100}\times CP \right]\]. After that we have to create an equation with the given values in the question. After calculating the equation we find the required answer.
Complete step-by-step answer:
Let us assume that the cost price (C.P) of A is x.
A sold a watch to B at 20% gain.
The formulae of selling price (S.P) for gain is,
\[SP=\left[ \dfrac{\left( 100+gain\% \right)}{100}\times CP \right]\]
Now putting the value of “gain” and C.P we get
\[\begin{align}
& sp=\left[ \dfrac{\left( 100+20 \right)}{100}\times x \right] \\
& \Rightarrow sp=\dfrac{120}{100}\times x \\
& \Rightarrow sp=\dfrac{12x}{10} \\
\end{align}\]
According to the question A sold a watch to B and B sold it to C. So the S.P of A is C.P of B.
The C.P of B is \[\dfrac{12x}{10}\].
B sold it to C at a loss of 10%. The formulae of selling price (S.P) for loss is,
\[SP=\left[ \dfrac{\left( 100-loss\% \right)}{100}\times CP \right]\]
Now putting the value of “loss” and C.P we get,
\[\begin{align}
& sp=\left[ \dfrac{\left( 100-10 \right)}{100}\times \dfrac{12x}{10} \right] \\
& \Rightarrow sp=\dfrac{90}{100}\times \dfrac{12x}{10} \\
& \Rightarrow sp=\dfrac{108x}{100} \\
& \Rightarrow sp=\dfrac{27x}{25} \\
\end{align}\]
The S.P of B is C.P of C. Now C bought the watch for Rs.216. So the selling price of B is equal to the cost price of C.
Creating the equation we got,
\[\begin{align}
& \dfrac{27x}{25}=216 \\
& \Rightarrow x=\dfrac{216\times 25}{27} \\
& \Rightarrow x=8\times 25 \\
& \Rightarrow x=200 \\
\end{align}\]
The cost price (C.P) of A is Rs200 (Option C).
Note: Students has to remember the formulas of selling price in time of profit is \[SP=\left[ \dfrac{\left( 100+gain\% \right)}{100}\times CP \right]\] and in time of loss is \[SP=\left[ \dfrac{\left( 100-loss\% \right)}{100}\times CP \right]\]. If they forget then they can use \[\left( gain\% \right)=\left[ \dfrac{SP-CP}{CP}\times 100 \right]\] and rearrange it as required. They have to know how to create an equation by giving values. They also have to understand the relation between cost price and selling price.
Complete step-by-step answer:
Let us assume that the cost price (C.P) of A is x.
A sold a watch to B at 20% gain.
The formulae of selling price (S.P) for gain is,
\[SP=\left[ \dfrac{\left( 100+gain\% \right)}{100}\times CP \right]\]
Now putting the value of “gain” and C.P we get
\[\begin{align}
& sp=\left[ \dfrac{\left( 100+20 \right)}{100}\times x \right] \\
& \Rightarrow sp=\dfrac{120}{100}\times x \\
& \Rightarrow sp=\dfrac{12x}{10} \\
\end{align}\]
According to the question A sold a watch to B and B sold it to C. So the S.P of A is C.P of B.
The C.P of B is \[\dfrac{12x}{10}\].
B sold it to C at a loss of 10%. The formulae of selling price (S.P) for loss is,
\[SP=\left[ \dfrac{\left( 100-loss\% \right)}{100}\times CP \right]\]
Now putting the value of “loss” and C.P we get,
\[\begin{align}
& sp=\left[ \dfrac{\left( 100-10 \right)}{100}\times \dfrac{12x}{10} \right] \\
& \Rightarrow sp=\dfrac{90}{100}\times \dfrac{12x}{10} \\
& \Rightarrow sp=\dfrac{108x}{100} \\
& \Rightarrow sp=\dfrac{27x}{25} \\
\end{align}\]
The S.P of B is C.P of C. Now C bought the watch for Rs.216. So the selling price of B is equal to the cost price of C.
Creating the equation we got,
\[\begin{align}
& \dfrac{27x}{25}=216 \\
& \Rightarrow x=\dfrac{216\times 25}{27} \\
& \Rightarrow x=8\times 25 \\
& \Rightarrow x=200 \\
\end{align}\]
The cost price (C.P) of A is Rs200 (Option C).
Note: Students has to remember the formulas of selling price in time of profit is \[SP=\left[ \dfrac{\left( 100+gain\% \right)}{100}\times CP \right]\] and in time of loss is \[SP=\left[ \dfrac{\left( 100-loss\% \right)}{100}\times CP \right]\]. If they forget then they can use \[\left( gain\% \right)=\left[ \dfrac{SP-CP}{CP}\times 100 \right]\] and rearrange it as required. They have to know how to create an equation by giving values. They also have to understand the relation between cost price and selling price.
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

