When a small piece of dry sodium is put in water, it reacts vigorously to produce:
(A) Nitrogen gas
(B) Hydrogen gas
(C) Carbon dioxide gas
(D) Sulphur dioxide
Answer
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Hint: Try to recall that sodium is a highly reactive alkali metal and on reaction with water it produces a gas which is the lightest substance known. Now, by using this you can easily find the correct option from the given ones.
Complete step by step solution:
* It is known to you that sodium is a highly reactive metal. That means it has a single electron in its outer shell which is readily lost in reactions, resulting in a much more stable complete outer electron shell.
* When sodium comes in contact with water, hydrogen gas is liberated and sodium hydroxide is generated that dissolved in water. The reaction of sodium with water is as follows: \[2Na(s) + 2{H_2}O \to 2NaOH + {H_2}\].
* The reaction is strongly exothermic, and the heat generated ignites the hydrogen gas.
* A small piece of sodium will dance on the surface of water with a hydrogen flame under and around it.
* A large piece of sodium can sink below the surface of the water, releasing a large amount of hydrogen and heat, resulting in a steam explosion that exposes the hydrogen gas to the atmosphere, where it will also likely explode.
Therefore, from above we can conclude that option B is the correct option to the given question.
Note:
* It should be remembered to you that sodium is kept/ preserved in kerosene so as to avoid its direct contact with the air. This is due to the high reactivity of sodium metal in air.
* Also, you should remember that the solution formed after the reaction of sodium with water is basic in nature due to dissolution of sodium hydroxide in water.
Complete step by step solution:
* It is known to you that sodium is a highly reactive metal. That means it has a single electron in its outer shell which is readily lost in reactions, resulting in a much more stable complete outer electron shell.
* When sodium comes in contact with water, hydrogen gas is liberated and sodium hydroxide is generated that dissolved in water. The reaction of sodium with water is as follows: \[2Na(s) + 2{H_2}O \to 2NaOH + {H_2}\].
* The reaction is strongly exothermic, and the heat generated ignites the hydrogen gas.
* A small piece of sodium will dance on the surface of water with a hydrogen flame under and around it.
* A large piece of sodium can sink below the surface of the water, releasing a large amount of hydrogen and heat, resulting in a steam explosion that exposes the hydrogen gas to the atmosphere, where it will also likely explode.
Therefore, from above we can conclude that option B is the correct option to the given question.
Note:
* It should be remembered to you that sodium is kept/ preserved in kerosene so as to avoid its direct contact with the air. This is due to the high reactivity of sodium metal in air.
* Also, you should remember that the solution formed after the reaction of sodium with water is basic in nature due to dissolution of sodium hydroxide in water.
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