Answer
Verified
398.1k+ views
Hint: This question needs to be approached in a different way. We have been given the statements and asked to check which is correct with our given conditions. So as we see in options we need to find the velocity of the particle and velocity of the wave. We will then equate the two velocities and if any one of the three statements is checked to be true that will be considered as our answer. If none of the three statements is true it will be clear that option D is our answer.
Formula Used: v = A \[\omega \]
Where, A = amplitude and \[\omega \] = angular frequency of the particle
V = f\[\lambda \]
Where, f= frequency of the wave and \[\lambda \] = wavelength
Complete step-by-step solution:
In the diagram above, the amplitude A is half of the total vibration path of the vibrating body. It is a measure of the change in a single period of time. In a sine or cosine wave amplitude is the perpendicular distance between the maximum height and the sinusoidal axis. Similarly, the wavelength is the distance between two crests or troughs of a wave.
We know that velocity of wave is given by the equation
V = f\[\lambda \]
We also know that frequency of a wave,
f = \[\dfrac{\omega }{2\pi }\]
Substitute the value of frequency in equation (1)
We get,
V = (\[\dfrac{\omega }{2\pi }\])(\[\lambda \]) ……………………… (A)
Similarly velocity of particle is given by,
v = A \[\omega \] ………………….. (B)
Now, let us assume V = v
Therefore,
From (A) and (B)
We can write,
(\[\dfrac{\omega }{2\pi }\])(\[\lambda \]) = A \[\omega \]
On dividing both sides by \[\omega \]
We get,
A = \[\dfrac{\lambda }{2\pi }\]
Therefore, the reverse statement that if A = \[\dfrac{\lambda }{2\pi }\] then V = v is true then by symmetric rule the statement V = v if A = \[\dfrac{\lambda }{2\pi }\] is also true.
Therefore, the correct answer is option A.
Note: There is no other way to solve this question. We must make the assumption that V = v and check if the statement holds true. In a sinusoidal wave moving at constant speed the frequency is inversely proportional to the wavelength \[\lambda \].
Formula Used: v = A \[\omega \]
Where, A = amplitude and \[\omega \] = angular frequency of the particle
V = f\[\lambda \]
Where, f= frequency of the wave and \[\lambda \] = wavelength
Complete step-by-step solution:
In the diagram above, the amplitude A is half of the total vibration path of the vibrating body. It is a measure of the change in a single period of time. In a sine or cosine wave amplitude is the perpendicular distance between the maximum height and the sinusoidal axis. Similarly, the wavelength is the distance between two crests or troughs of a wave.
We know that velocity of wave is given by the equation
V = f\[\lambda \]
We also know that frequency of a wave,
f = \[\dfrac{\omega }{2\pi }\]
Substitute the value of frequency in equation (1)
We get,
V = (\[\dfrac{\omega }{2\pi }\])(\[\lambda \]) ……………………… (A)
Similarly velocity of particle is given by,
v = A \[\omega \] ………………….. (B)
Now, let us assume V = v
Therefore,
From (A) and (B)
We can write,
(\[\dfrac{\omega }{2\pi }\])(\[\lambda \]) = A \[\omega \]
On dividing both sides by \[\omega \]
We get,
A = \[\dfrac{\lambda }{2\pi }\]
Therefore, the reverse statement that if A = \[\dfrac{\lambda }{2\pi }\] then V = v is true then by symmetric rule the statement V = v if A = \[\dfrac{\lambda }{2\pi }\] is also true.
Therefore, the correct answer is option A.
Note: There is no other way to solve this question. We must make the assumption that V = v and check if the statement holds true. In a sinusoidal wave moving at constant speed the frequency is inversely proportional to the wavelength \[\lambda \].
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Select the word that is correctly spelled a Twelveth class 10 english CBSE
How fast is 60 miles per hour in kilometres per ho class 10 maths CBSE
What organs are located on the left side of your body class 11 biology CBSE