Question

A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% bananas were rotten. Find the percentage of fruits in good condition.
(A) 80% (B) 86.8% (C) 87.8% (D) 88%

Answer 1

Hint: Percentage is a ratio of number which is denoted by the sign “%”. We have to apply the key formula of percentage first & then find no. of good & rotten oranges & bananas separately & finally calculate how much percentage it is of total no. of fruits.
Like 10% of 200 will be $200 \times \dfrac{{10}}{{100}} = 20$

Complete step-by-step answer: According to given data in the question ,
Total no. of oranges = 600
Rotten no. of oranges = $600 \times \dfrac{{15}}{{100}} = 90$ nos.
Good no. of oranges = $\left( {600 - 90} \right) = 510$ nos.
Total no. of bananas = 400
Rotten no. of bananas = $400 \times \dfrac{8}{{100}} = 32$ nos.
Good no. of bananas = $\left( {400 - 32} \right) = 368$ nos.
$\therefore $ Total no. of fruits = $\left( {600 + 400} \right) = 1000$
Total no. of good fruits = $\left( {510 + 368} \right) = 878$
$\therefore $ Percentage of good fruits = $\dfrac{{878}}{{1000}} \times 100 = 87.8\% $
Percentage of good fruits = 87.8%

Note: Read the question carefully & remember the formula of percentage to be applied. Calculations should be done carefully to avoid silly mistakes.