
A sample of gas has a volume of 0.2 litres measured at 1 atm pressure and $\text{0}{}^\circ \text{C}$. At the same pressure, at $273{}^\circ \text{C}$, its volume will become:
(A) 0.1 litre
(B) 0.4 litre
(C) 0.8 litre
(D) 0.6 litre
Answer
576k+ views
Hint: For this problem, we have to study Charles' law according to which the volume is directly proportional to the temperature when the pressure is constant. So by putting all the values we can calculate the volume.
Complete step by step solution:
-In the given question, we have to calculate the volume when the pressure remains the same but the temperature becomes $273{}^\circ \text{C}$.
-As we know that Charles law gives us the relationship between volume and temperature when the pressure is constant.
-According to the Charle's law volume is directly proportional to the temperature such that:
\[\dfrac{{{\text{V}}_{1}}}{{{\text{V}}_{2}}}\text{ }\,\text{= }\dfrac{{{\text{T}}_{1}}}{{{\text{T}}_{2}}}\] ….. (1)
-Here, V is the volume of the gas and T is the temperature of the gas in Kelvin.
-Now, it is given that at a temperature $\text{0}{}^\circ \text{C}$ the volume of the gas is 0.2 litres so we have to find the volume of gas at temperature $273{}^\circ \text{C}$.
-So, here \[{{\text{V}}_{1}}\] is equal to 0.2 litres and \[{{\text{T}}_{1}}\] $\text{273}{}^\circ \text{C}$ or 546K is whereas the value of \[{{\text{T}}_{2}}\] is $\text{0}{}^\circ \text{C}$ or 273k and we have to calculate \[{{\text{V}}_{2}}\].
-So, we can also write the equation first as:
\[{{\text{V}}_{2}}\text{ = }\dfrac{{{\text{V}}_{1}}\text{ }\times \text{ }{{\text{T}}_{2}}}{{{\text{T}}_{1}}}\]
-Now, by putting all the values we will get:
\[{{\text{V}}_{2}}\text{ = }\dfrac{\text{0}\text{.2 }\times \text{ 546}}{273}\text{ = 0}\text{.4 litres}\]
-So, the volume of gas at $\text{0}{}^\circ \text{C}$ is equal to 0.4 litres.
Therefore, option (B) is the correct answer.
Note: Just like Charles law, Boyle's law was also given, according to which the inverse relationship between volume and pressure is given when the temperature is constant. Moreover, Gay-Lussac law was also given, according to which the pressure has a direct effect on temperature when the volume is kept constant.
Complete step by step solution:
-In the given question, we have to calculate the volume when the pressure remains the same but the temperature becomes $273{}^\circ \text{C}$.
-As we know that Charles law gives us the relationship between volume and temperature when the pressure is constant.
-According to the Charle's law volume is directly proportional to the temperature such that:
\[\dfrac{{{\text{V}}_{1}}}{{{\text{V}}_{2}}}\text{ }\,\text{= }\dfrac{{{\text{T}}_{1}}}{{{\text{T}}_{2}}}\] ….. (1)
-Here, V is the volume of the gas and T is the temperature of the gas in Kelvin.
-Now, it is given that at a temperature $\text{0}{}^\circ \text{C}$ the volume of the gas is 0.2 litres so we have to find the volume of gas at temperature $273{}^\circ \text{C}$.
-So, here \[{{\text{V}}_{1}}\] is equal to 0.2 litres and \[{{\text{T}}_{1}}\] $\text{273}{}^\circ \text{C}$ or 546K is whereas the value of \[{{\text{T}}_{2}}\] is $\text{0}{}^\circ \text{C}$ or 273k and we have to calculate \[{{\text{V}}_{2}}\].
-So, we can also write the equation first as:
\[{{\text{V}}_{2}}\text{ = }\dfrac{{{\text{V}}_{1}}\text{ }\times \text{ }{{\text{T}}_{2}}}{{{\text{T}}_{1}}}\]
-Now, by putting all the values we will get:
\[{{\text{V}}_{2}}\text{ = }\dfrac{\text{0}\text{.2 }\times \text{ 546}}{273}\text{ = 0}\text{.4 litres}\]
-So, the volume of gas at $\text{0}{}^\circ \text{C}$ is equal to 0.4 litres.
Therefore, option (B) is the correct answer.
Note: Just like Charles law, Boyle's law was also given, according to which the inverse relationship between volume and pressure is given when the temperature is constant. Moreover, Gay-Lussac law was also given, according to which the pressure has a direct effect on temperature when the volume is kept constant.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

