Question

A ribbon of length $5\dfrac{1}{2}m$ is cut into small pieces each of length $\dfrac{3}{4}m$. Number of pieces will be
A. $5$
B. $6$
C. $7$
D. $8$

Answer 1

Hint: These kinds of questions deal with the division of fractions and also the division of quantities into smaller quantities to get a larger number of products. In this case a bigger ribbon is cut up into smaller pieces to get a larger number of smaller ribbons. These ribbons have a specified length that needs to be the divisor for the bigger ribbon. Number of pieces of the smaller ribbon depends on how many small ribbons can fit in the smaller ribbon. We first need to convert mixed fractions into proper fractions to divide though.

Complete step-by-step answer:
These kinds of questions deal with the division of fractions and also the division of quantities into smaller quantities to get a larger number of products.
In this case a bigger ribbon is cut up into smaller pieces to get a larger number of smaller ribbons. These ribbons have a specified length that needs to be the divisor for the bigger ribbon.
Number of pieces of the smaller ribbon depends on how many small ribbons can fit in the smaller ribbon.

The length of the bigger ribbon is given as $5\dfrac{1}{2}m = \dfrac{{11}}{2}m$
The length of the smaller ribbon is given as $\dfrac{3}{4}m$
We divide length of longer ribbon with length of smaller ribbon to get number of ribbons,
That is,
Number of ribbons $ = \dfrac{{11}}{2} \div \dfrac{3}{4}$
$ = \dfrac{{11}}{2} \times \dfrac{4}{3} \\$
$= \dfrac{{22}}{3} \\$
$ = 7\dfrac{1}{3}$

Since, the number of ribbons can't be a fraction, we take the most number of ribbons possible as the answer, that is, $\left( c \right)7$.

Note: > Don’t forget to convert the given length into mixed fractions.
> If the answer is in mixed fractions, that means some ribbon cloth will be left when all smaller ribbons possible are cut up.