
A regular hexagon is inscribed in a circle. If the area of the hexagon is \[24\sqrt{3}c{{m}^{2}}\], find the area of the circle. (Use \[\pi =3.14\])
Answer
597k+ views
Hint: Find the side or radius of the circle by using the area of regular hexagon formula. Area is given so find the side of the hexagon, which is equal to radius of circle. Find the area of the circle.
Complete step by step answer:
Consider the hexagon that is drawn. Let us mark the hexagon as ABCDEF. It is said that a regular hexagon is inscribed in a circle. Let the center of the circle be denoted as ‘O’. Let the radius of the circle be denoted as O. Let the radius of the circle be taken as ‘a’. And the side of the hexagon is also ‘a’.
We have been given the area of the regular hexagon as \[24\sqrt{3}c{{m}^{2}}\].
We need to find the side ‘a’.
We know the formula for hexagon area\[=\dfrac{3\sqrt{3}{{a}^{2}}}{2}\]
Area of regular hexagon = \[24\sqrt{3}\].
\[\therefore \dfrac{3\sqrt{3}{{a}^{2}}}{2}=24\sqrt{3}\]
Cross multiply and find the value of a.
\[{{a}^{2}}=\dfrac{24\sqrt{3}\times a}{3\sqrt{3}}=16\]
\[a=\sqrt{16}=4\]cm
Thus we got the side of a regular hexagon, a = 4cm.
We said that the radius of the circle = a = 4cm.
\[\therefore \] Area of circle is given by \[\pi {{r}^{2}}\], where r is radius which is equal to a.
\[\therefore \] Area of circle\[=\pi {{a}^{2}}\]
\[\begin{align}
& =3.14\times {{4}^{2}} \\
& =3.14\times 4\times 4 \\
& =50.24c{{m}^{2}} \\
\end{align}\]
Thus we got the area of the circle as \[50.24c{{m}^{2}}\].
Note: Formulas to find the area of a hexagon is not something we commonly use. So in case of questions like this remember to learn the formula. Without the formula, you can’t find the sides of the hexagon.Students should remember the formulas for solving these types of problems.
Complete step by step answer:
Consider the hexagon that is drawn. Let us mark the hexagon as ABCDEF. It is said that a regular hexagon is inscribed in a circle. Let the center of the circle be denoted as ‘O’. Let the radius of the circle be denoted as O. Let the radius of the circle be taken as ‘a’. And the side of the hexagon is also ‘a’.
We have been given the area of the regular hexagon as \[24\sqrt{3}c{{m}^{2}}\].
We need to find the side ‘a’.
We know the formula for hexagon area\[=\dfrac{3\sqrt{3}{{a}^{2}}}{2}\]
Area of regular hexagon = \[24\sqrt{3}\].
\[\therefore \dfrac{3\sqrt{3}{{a}^{2}}}{2}=24\sqrt{3}\]
Cross multiply and find the value of a.
\[{{a}^{2}}=\dfrac{24\sqrt{3}\times a}{3\sqrt{3}}=16\]
\[a=\sqrt{16}=4\]cm
Thus we got the side of a regular hexagon, a = 4cm.
We said that the radius of the circle = a = 4cm.
\[\therefore \] Area of circle is given by \[\pi {{r}^{2}}\], where r is radius which is equal to a.
\[\therefore \] Area of circle\[=\pi {{a}^{2}}\]
\[\begin{align}
& =3.14\times {{4}^{2}} \\
& =3.14\times 4\times 4 \\
& =50.24c{{m}^{2}} \\
\end{align}\]
Thus we got the area of the circle as \[50.24c{{m}^{2}}\].
Note: Formulas to find the area of a hexagon is not something we commonly use. So in case of questions like this remember to learn the formula. Without the formula, you can’t find the sides of the hexagon.Students should remember the formulas for solving these types of problems.
Recently Updated Pages
Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Plot a graph between potential difference V and current class 12 physics CBSE

