Question

When a red filtered light is shown on a red flower, why do the leaves look black?

Answer 1

Hint: In the event that you pass white light through a red filter, at that point red light comes out the opposite side. This is on the grounds that the red filter just permits red light through. Different tones (frequencies) of the range are consumed. Also, a green channel just permits green light through.

Complete answer:
The flower is absorbing all frequencies of light shone on it. White light is really a blend of each frequency of obvious light. At the point when any item gives off an impression of being sure shading when acquainted with white light, it is really retaining each frequency of light aside from the shading it seems, by all accounts, to be. For this situation, the bloom is retaining each frequency of light aside from red. The red light that isn't retained is rather reflected, so the red light is reflected into your eye and it seems red.
At the point when red-separated light hits this bloom, the white light has no frequencies of red light in it. Accordingly, the bloom retains 100% of the light shone on it, mirroring no light and subsequently seeming dark (the "shading" that results from the nonattendance of light).

Note: An item mirrors its own shading however assimilates different tones, it seems red shading bloom with green leaves is seen in green light and afterward in red light. At the point when seen in green light, blossom ingests green light subsequently it seems dark, however leaves mirrors green light, henceforth leaves show up as green. At the point when seen in red light, bloom mirrors red light henceforth it seems red, however leaves assimilates red light, consequently leaves show up as dark.