Question

A rectangular hall is \[22\] m long and \[15.5\] m broad. Find the area of the carpet which covers it.

Answer 1

Hint:
Here we will substitute the given dimensions of length and breadth of the given hall in the formula of area of a rectangle to find the required area of the carpet. The area of a rectangle is the space enclosed by the perimeter i.e., the boundary of the rectangle.

Formula used:
Area of a rectangle \[ = l \times b\], where \[l\] denotes the length of the rectangle and \[b\] denotes the breadth of the rectangle.

Complete step by step solution:
We are given that a rectangular hall is \[22\] m long and \[15.5\] m broad. We are required to find the area of the carpet covering the hall. The area of a rectangle is measured by calculating the product of the length and the breadth of the rectangle. Here, the length of the rectangular hall is \[l = 22\] m and the breadth of the hall is \[b = 15.5\] m.
Hence, the area of the carpet covering the rectangular hall is
\[A = l \times b = 22 \times 15.5\]
Multiplying the terms, we get
\[ \Rightarrow A = 341{{\rm{m}}^2}\]

Therefore, the area of the carpet covering the rectangular hall is \[341{{\rm{m}}^2}\].

Note:
There is a significant difference between the terms “area” and “perimeter”. The perimeter of a closed figure is the length of its boundary. The perimeter of a rectangle is twice the sum of its length and breadth i.e., \[2(l + b)\]. In the given problem, the perimeter of the rectangular hall is \[2(22 + 15.5) = 75\]m. Now a rectangle is a two-dimensional figure whose opposite sides are equal and parallel. Moreover, each internal angle of a rectangle is \[90^\circ \].