
A rectangular classroom is of length 27m. If its area is 594 square meters, what is its breadth?
Answer
484.2k+ views
Hint: We solve this question by first assuming the breadth of the classroom as $b$. Then we consider the formula for the area of the rectangle as the classroom is rectangular, $Area=\left( length \right)\times \left( breadth \right)$. Then we substitute the value of length given and breadth $b$ in it. Then we substitute the value of the area given in the question. Then we simplify the obtained equation to find the value of $b$, that is the breadth of the classroom.
Complete step-by-step answer:
We are given that the length of the classroom is 27 meters.
We are also given that area of the class room is 594 square meters.
We need to find the breadth of the classroom. So, let us assume that the breadth of the class room is $b$ meters.
As we are given that the class room is rectangular, the diagram of the classroom looks like below.
Now let us consider the formula for the area of the rectangle.
$Area=\left( length \right)\times \left( breadth \right)$
Using this formula, we can substitute the given value of length and breadth in it. Then we get,
$\Rightarrow Area=27\times b$
As we are given that area of the class room is equal to 594 square meters, let us substitute it in the above equation. Then we get,
$\Rightarrow 594=27\times b$
Taking 27 to other side we get,
$\Rightarrow b=\dfrac{594}{27}$
Calculating the above value, we get the value of b as,
$\Rightarrow b=22$
So, the breadth of the class room is 22 meters.
Hence, the answer is 22 meters.
Note: The common mistake that one makes while solving this question is one might confuse the formula for area of the rectangle with the perimeter of the rectangle, that is one might the formula for area of rectangle as $2\left( length+breadth \right)$ instead of taking it as $\left( length \right)\times \left( breadth \right)$.
Complete step-by-step answer:
We are given that the length of the classroom is 27 meters.
We are also given that area of the class room is 594 square meters.
We need to find the breadth of the classroom. So, let us assume that the breadth of the class room is $b$ meters.
As we are given that the class room is rectangular, the diagram of the classroom looks like below.

Now let us consider the formula for the area of the rectangle.
$Area=\left( length \right)\times \left( breadth \right)$
Using this formula, we can substitute the given value of length and breadth in it. Then we get,
$\Rightarrow Area=27\times b$
As we are given that area of the class room is equal to 594 square meters, let us substitute it in the above equation. Then we get,
$\Rightarrow 594=27\times b$
Taking 27 to other side we get,
$\Rightarrow b=\dfrac{594}{27}$
Calculating the above value, we get the value of b as,
$\Rightarrow b=22$
So, the breadth of the class room is 22 meters.
Hence, the answer is 22 meters.
Note: The common mistake that one makes while solving this question is one might confuse the formula for area of the rectangle with the perimeter of the rectangle, that is one might the formula for area of rectangle as $2\left( length+breadth \right)$ instead of taking it as $\left( length \right)\times \left( breadth \right)$.
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