A rational number lie between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] is--
A. \[\dfrac{7}{{24}}\]
B. \[0.29\]
C. \[\dfrac{{13}}{{48}}\]
D.All of these.
Answer
589.5k+ views
Hint: Firstly note the definition of rational number and irrational number. Rational number is a number that can be expressed in the form of \[\dfrac{p}{q}\] , where \[p\] and \[q\] are integers. More importantly \[q \ne 0\] . If \[q\] becomes zero we will get infinity. Irrational means no ratio. While in case of irrational numbers it cannot be expressed as a simple fraction. For example, \[\sqrt 2 \] and \[\sqrt 3 \] .
Complete step-by-step answer:
We know that if \[a\] and \[b\] are rational then \[\dfrac{{a + b}}{2}\] is also rational which lies between \[a\] and \[b\] .
Now, the rationales that lies between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] is
\[ = \dfrac{{\left( {\dfrac{1}{3} + \dfrac{1}{4}} \right)}}{2}\]
L.C.M. of 3 and 4 is 12. On simplifying we get,
\[ = \dfrac{{\left( {\dfrac{{4 + 3}}{{12}}} \right)}}{2}\]
\[ = \dfrac{{\left( {\dfrac{7}{{12}}} \right)}}{2}\]
\[ = \dfrac{7}{{24}}\]
Since \[\dfrac{7}{{24}} = 0.29166\] , \[\dfrac{1}{4} = 0.25\] and \[\dfrac{1}{3} = 0.33\] .
Since given two options are correct. Let's find out the other rational number lies between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] .
Since \[\dfrac{7}{{24}}\] lies in between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] . Then the rationales that lies between \[\dfrac{1}{4}\] and \[\dfrac{7}{{24}}\] is also lies between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] .
Then, we haves
\[ = \dfrac{{\left( {\dfrac{1}{4} + \dfrac{1}{{24}}} \right)}}{2}\]
L.C.M. of 4 and 24 is 24. On simplifying we get,
\[ = \dfrac{{\left( {\dfrac{{6 + 7}}{{24}}} \right)}}{2}\]
\[ = \dfrac{{\left( {\dfrac{{13}}{{24}}} \right)}}{2}\]
\[ = \dfrac{{13}}{{48}}\] .
Thus, all the obtained rational between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] are
\[\dfrac{7}{{24}}\] , \[0.29\] and \[\dfrac{{13}}{{48}}\] .
So, the correct answer is “Option D”.
Note: We can also find the rational between \[\dfrac{1}{3}\] and \[\dfrac{7}{{24}}\] , which will also lies in \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] . But we had obtained the answer earlier so we stopped there only. Irrational numbers are not a finite number. Rational numbers are finite. We know that the sum of two rationals is rational. Follow the same procedure for finding rationales that lies between given two rationales.
Complete step-by-step answer:
We know that if \[a\] and \[b\] are rational then \[\dfrac{{a + b}}{2}\] is also rational which lies between \[a\] and \[b\] .
Now, the rationales that lies between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] is
\[ = \dfrac{{\left( {\dfrac{1}{3} + \dfrac{1}{4}} \right)}}{2}\]
L.C.M. of 3 and 4 is 12. On simplifying we get,
\[ = \dfrac{{\left( {\dfrac{{4 + 3}}{{12}}} \right)}}{2}\]
\[ = \dfrac{{\left( {\dfrac{7}{{12}}} \right)}}{2}\]
\[ = \dfrac{7}{{24}}\]
Since \[\dfrac{7}{{24}} = 0.29166\] , \[\dfrac{1}{4} = 0.25\] and \[\dfrac{1}{3} = 0.33\] .
Since given two options are correct. Let's find out the other rational number lies between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] .
Since \[\dfrac{7}{{24}}\] lies in between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] . Then the rationales that lies between \[\dfrac{1}{4}\] and \[\dfrac{7}{{24}}\] is also lies between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] .
Then, we haves
\[ = \dfrac{{\left( {\dfrac{1}{4} + \dfrac{1}{{24}}} \right)}}{2}\]
L.C.M. of 4 and 24 is 24. On simplifying we get,
\[ = \dfrac{{\left( {\dfrac{{6 + 7}}{{24}}} \right)}}{2}\]
\[ = \dfrac{{\left( {\dfrac{{13}}{{24}}} \right)}}{2}\]
\[ = \dfrac{{13}}{{48}}\] .
Thus, all the obtained rational between \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] are
\[\dfrac{7}{{24}}\] , \[0.29\] and \[\dfrac{{13}}{{48}}\] .
So, the correct answer is “Option D”.
Note: We can also find the rational between \[\dfrac{1}{3}\] and \[\dfrac{7}{{24}}\] , which will also lies in \[\dfrac{1}{4}\] and \[\dfrac{1}{3}\] . But we had obtained the answer earlier so we stopped there only. Irrational numbers are not a finite number. Rational numbers are finite. We know that the sum of two rationals is rational. Follow the same procedure for finding rationales that lies between given two rationales.
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