A quantity of 50g of water is saturated with HCl gas to get 75 ml of solution containing 40% HCl, by mass. The density of the solution forms is--------.
A. 1.11 g/ml
B. 0.4 g/ml
C. 0.9 g/ml
D. 0.99 g/ml
Answer
663.9k+ views
Hint: Density of the solution is nothing but the number of grams of the solute present in the total volume of the solution. There is a formula to calculate the density of the solution and it is as follows.
\[\text{Density=}\dfrac{\text{mass of the solution}}{\text{total volume of the solution}}\]
Complete step by step answer:
- In the question it is given that a quantity of 50 g of water is saturated with HCl to get 75 ml of 40% HCl by mass.
- 40% means 40 g of HCl in 100 g of solution.
-Then the mass of water = 100 g - 40 g = 60 g
-Therefore 40 g of HCl is present in 60 g of water.
- Assume that a ‘y’ gram of HCl is present in 50 g of water.
-Then
\[\begin{align}
& \dfrac{40}{y}=\dfrac{60}{50} \\
& y=33.33g \\
\end{align}\]
-Means 33.33 g of HCl is present in 50 g of water.
-Therefore total mass of the solution = 50 + 33.33 = 83.33 g.
-Total volume of the given solution in the question is 75 ml.
-Substitute the known values in the above equation to get the density solution.
\[\begin{align}
& \text{Density=}\dfrac{\text{mass of the solution}}{\text{total volume of the solution}} \\
& Density = \dfrac{83.33}{75} = 1.11g \\
\end{align}\]
-Therefore the density of the solution is 1.11 g.
So, the correct answer is “Option A”.
Note: Saturated HCl means, no more HCl is going to dissolve in a particular solution after adding some amount of HCl. But by heating the saturated solution we can dissolve more HCl into saturated solution. Then the resulting solution is called supersaturated solution.
\[\text{Density=}\dfrac{\text{mass of the solution}}{\text{total volume of the solution}}\]
Complete step by step answer:
- In the question it is given that a quantity of 50 g of water is saturated with HCl to get 75 ml of 40% HCl by mass.
- 40% means 40 g of HCl in 100 g of solution.
-Then the mass of water = 100 g - 40 g = 60 g
-Therefore 40 g of HCl is present in 60 g of water.
- Assume that a ‘y’ gram of HCl is present in 50 g of water.
-Then
\[\begin{align}
& \dfrac{40}{y}=\dfrac{60}{50} \\
& y=33.33g \\
\end{align}\]
-Means 33.33 g of HCl is present in 50 g of water.
-Therefore total mass of the solution = 50 + 33.33 = 83.33 g.
-Total volume of the given solution in the question is 75 ml.
-Substitute the known values in the above equation to get the density solution.
\[\begin{align}
& \text{Density=}\dfrac{\text{mass of the solution}}{\text{total volume of the solution}} \\
& Density = \dfrac{83.33}{75} = 1.11g \\
\end{align}\]
-Therefore the density of the solution is 1.11 g.
So, the correct answer is “Option A”.
Note: Saturated HCl means, no more HCl is going to dissolve in a particular solution after adding some amount of HCl. But by heating the saturated solution we can dissolve more HCl into saturated solution. Then the resulting solution is called supersaturated solution.
Recently Updated Pages
Which will be the least stable resonating structure class 11 chemistry CBSE

How many 5 digit telephone numbers can be construc-class-11-maths-CBSE

How do you find the angle of the resultant vector class 11 physics CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is the need and importance of classification class 11 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

