Question

A pure tall Pea plant is crossed with a pure dwarf Pea plant. The progeny is self-pollinated. The ratio breeding tall Pea plants to true breeding dwarf Pea plants shall be
A. 2:1
B. 1:1
C. 3:1
D. 1:2.

Answer 1

Hint:The trait that can express itself in homozygous condition only is known as recessive trait. The cross between tall and short pea plant produces the tall progeny. The tall progeny is present in heterozygous condition and the tall trait is dominant that expresses itself and hides the expression of short traits.

Complete answer:
To answer this question, first, we need to know about the Medel’s law of inheritance. The Mendel’s laws of inheritance contain the law of segregation, law of dominance and law of independent assortment. The law of segregation refers that each individual consists of two alleles and only one allele is transferred to the offspring. The law of independent assortment refers that the hereditary of one pair of genes is independent of hereditary of another pair.The F1 progeny produced by the crossing of pure tall pea plant with pure dwarf pea plant, is put through to self pollination, in the upcoming generation 1 homozygous tall 2 heterozygous tall 1 homozygous dwarf progeny are produced. The ratio obtained between the homozygous tall and homozygous dwarf is 1:1.

Thus, the correct option is B. i.e. 1:1.
Note:Genotype of half of the offspring would be similar with one parent and the remaining to the other parent. All the F1 , offsprings of the cross are heterozygous so permitted self-pollination is enough to develop F2 offspring. Mendel deliberates to recognize the hereditary of the particular selected trait above generations.