
A pulse of light of duration $100ns$ is absorbed completely by a small object initially at rest. Power of the pulse is $30mW$ and the speed of light is $3 \times {10^8}m{s^{ - 2}}$ . The final momentum of the object is
A. $0.3 \times {10^{ - 17}}kgm{s^{ - 1}}$
B. $1.0 \times {10^{ - 17}}kgm{s^{ - 1}}$
C. $3.0 \times {10^{ - 17}}kgm{s^{ - 1}}$
D. $9.0 \times {10^{ - 17}}kgm{s^{ - 1}}$
Answer
559.2k+ views
Hint:In this question, we are given that a pulse of is absorbed into an object and we have to find the momentum of the final object. There is movement of photons from the wave pulse to the object so here we can apply the de Broglie formula to find the momentum.
Complete Step by Step Answer:
Let us consider a pulse is absorbed completely by an object initially at rest. Then the force with which the pulse attacks the object is given by the product of the power of the pulse and the duration of the pulse and these values are being given in the question.
Incident Energy $E = Pt$ $ \ldots \ldots \left( 1 \right)$
Where $P = 30mW$ is the power and $t = 100ns$ is the duration of the pulse
Now, we have to find the final momentum of the object. We can use de Broglie equation here, writing the de Broglie wavelength $\lambda = \dfrac{h}{p}$
Energy of the photon be given as $E = pc$ $ \ldots \ldots \left( 2 \right)$
where $p$ is the momentum of the object after absorbed
solving the two marked equations
$
Pt = pc \\
\Rightarrow p = \dfrac{{Pt}}{c} \\
$
Substituting the given values
By converting the power which is given in megawatt $\left( {{{10}^{ - 3}}} \right)$ to watt and time in nanoseconds $\left( {{{10}^{ - 9}}} \right)$ to seconds
$p = \dfrac{{30 \times {{10}^{ - 3}} \times 100 \times {{10}^{ - 9}}}}{{3 \times {{10}^8}}} \\
\therefore p = {10^{ - 17}}kgm{s^{ - 1}}$
Hence, our correct option is B.
Note:When a light wave encounters an object, it can be absorbed, transmitted, reflected, polarized, diffracted depending on the composition of the object or the wavelength of the wave. Absorption occurs when the photons from the incident light cause the object to vibrate.
Complete Step by Step Answer:
Let us consider a pulse is absorbed completely by an object initially at rest. Then the force with which the pulse attacks the object is given by the product of the power of the pulse and the duration of the pulse and these values are being given in the question.
Incident Energy $E = Pt$ $ \ldots \ldots \left( 1 \right)$
Where $P = 30mW$ is the power and $t = 100ns$ is the duration of the pulse
Now, we have to find the final momentum of the object. We can use de Broglie equation here, writing the de Broglie wavelength $\lambda = \dfrac{h}{p}$
Energy of the photon be given as $E = pc$ $ \ldots \ldots \left( 2 \right)$
where $p$ is the momentum of the object after absorbed
solving the two marked equations
$
Pt = pc \\
\Rightarrow p = \dfrac{{Pt}}{c} \\
$
Substituting the given values
By converting the power which is given in megawatt $\left( {{{10}^{ - 3}}} \right)$ to watt and time in nanoseconds $\left( {{{10}^{ - 9}}} \right)$ to seconds
$p = \dfrac{{30 \times {{10}^{ - 3}} \times 100 \times {{10}^{ - 9}}}}{{3 \times {{10}^8}}} \\
\therefore p = {10^{ - 17}}kgm{s^{ - 1}}$
Hence, our correct option is B.
Note:When a light wave encounters an object, it can be absorbed, transmitted, reflected, polarized, diffracted depending on the composition of the object or the wavelength of the wave. Absorption occurs when the photons from the incident light cause the object to vibrate.
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