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A point object O is placed on the principal axis of a convex lens of focal length f= 20cm at a distance of 40cm to the left of it. The diameter of the lens is 10cm. An eye is placed 60cm to the right of the lens and a distance h below the principal axis. The maximum value of h to see the image is
A. Zero
B. 2.5cm
C. 5cm
D. 10cm

Answer
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Hint: This type of optics questions always utilize the lens formula. Here we can calculate image distance using this formula. Then simple mathematical symmetry of triangles aids us in calculating the value of h.
Formula Used: Lens Formula:
1f=1v1u
Where f is the focal length of lens, v is the distance of image from lens and u is the distance of object from lens.

Complete Step-by-Step solution:
While solving optics questions like this, lens formulas always come handy. We have the following values given to us.
f=20cm
u=-40cm
Solving for v using lens formula, we get
120=1v1(40)120=1v+1401v=1201401v=21401v=140v=40cm
This means that the image is formed at the center of curvature. Therefore, we can draw the ray diagram as follows.


seo images


Now in the figure, ΔCED and ΔCAB are symmetric. So we have
ABDE=BCDC5h=40205h=2h=52h=2.5cm
This is the required answer. Hence, the correct option is option B.
Additional Information:
We can also calculate the magnification of an object using the following formula.
M=hiho=vu
where hi is the height of the image and ho is the height of the object.

Note: The student must take care of the convention followed for the signs of various distances. Take care of the negative sign for u and positive sign for v. All distances to the left of the lens are taken as negative whereas all the distances to the right of the lens are taken as positive.