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A plane left an airport at 1:23 P.M. It arrived at its destination in the same time zone at 4:10 P.M. How long was the flight?
(A) 1 hr 47 min
(B) 2 hr 47 min
(C) 1 hr 20 min
(D) 2 hr 20 min

Answer
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509.1k+ views
Hint: Express the given times in hours and minutes. Then subtract the arrival time from the departure time to get the answer.

Complete step-by-step answer:
We are given the departure and arrival times of a plane at an airport.
We need to know the duration of the flight.
Departure time = 1:23 P.M. = 1 hr 23 min
Arrival time = 4:10 P.M. = 4 hr 10 min
Duration of the flight = arrival time $ - $ departure time = 4 hr 10 min $ - $ 1 hr 23 min
To find the difference between the minute parts of the times, we subtract 23 from \[60 + 10 = 70\]minutes as 1 hr = 60 min. This means that we have borrowed an hour from 4 hours.
Therefore, the duration of the flight = 3 hr 70 min $ - $ 1 hr 23 min = 2 hr 47 min.
So, the correct answer is “Option B”.

Note: If the unit of the departure time is P.M. and the unit of arrival time is A.M., one must not make the mistake of taking the difference directly. It is essential that you express the departure time in the 24 hours format.
For example the 24 hour format of 1:23 P.M. is 13:23 P.M. Only then proceed with the calculation.