A pipe's lower end is immersed in water such that the length of the air column from the top open end has a certain length $25 \mathrm{~cm}$. The speed of sound in air is $350 \mathrm{~m} / \mathrm{s}$. The air column is found to resonate with a tuning fork of frequency $1750 \mathrm{~Hz}$. By what minimum distance should the pipe be raised in order to make the air column resonate again with the same tuning fork?
A. $7 \mathrm{~cm}$
B.$5~\text{cm}$
C.$35 \mathrm{~cm}$
D. $10 \mathrm{~cm}$
Answer
632.7k+ views
Hint: An air column can be defined in a certain space as the weight or pressure of the air. Calculate The Initial length of the pipe and the minimum increase in length of the air column after increasing the length of the pipe by $\mathrm{Lm}$ after this Equate the equation by the frequency formula to get the minimum distance by the pipe.
Formula used:
$v_{\mathrm{n}}=\dfrac{(2 \mathrm{n}-1) \mathrm{v}}{4 \mathrm{~L}} \quad$
Complete answer:
Resonance describes the increased amplitude phenomenon that occurs when the frequency of a force applied periodically is equal to or close to the natural frequency of the system on which it acts.
Given: speed of sound in air, $\mathrm{v}=350 \mathrm{~m} / \mathrm{s}$
For one sided closed pipe:
Frequency, $v_{\mathrm{n}}=\dfrac{(2 \mathrm{n}-1) \mathrm{v}}{4 \mathrm{~L}} \quad$ where $\mathrm{n}=1,2,3$
When length of the pipe is $25 \mathrm{~cm}$ OR $0.25 \mathrm{~m}, \quad 1750=\dfrac{(2 \mathrm{n}-1) 350}{4 \times 0.25}$
$\text{n}=3$
Now let the length of the pipe after raising be $\mathrm{Lm}$.
For minimum increase in length of air column, $\mathrm{n}=3+1=4$
For minimum increase in length of air column, $\mathrm{n}=3+1=4$
$1750=\dfrac{(2\times 4-1)350}{4\times \text{L}}$
gives $\mathrm{L}=0.35 \mathrm{~m}$
Thus, the distance by which the pipe is raised $=0.35-0.25=0.1~\text{m}$
The distance by which the pipe is raised $=0.35-0.25=0.1 \mathrm{~m}=10 \mathrm{~cm}$
So,the Correct option is (D) .
Note:
Resonance describes the increased amplitude phenomenon that occurs when a periodically applied force is frequently applied. In a resonance column apparatus, air column vibrations can be set up. The condition for resonance is this. This occurs only when the air column length is proportional to one-fourth of the sound wavelength of sound waves that have a frequency equal to the tuning fork frequency.
Formula used:
$v_{\mathrm{n}}=\dfrac{(2 \mathrm{n}-1) \mathrm{v}}{4 \mathrm{~L}} \quad$
Complete answer:
Resonance describes the increased amplitude phenomenon that occurs when the frequency of a force applied periodically is equal to or close to the natural frequency of the system on which it acts.
Given: speed of sound in air, $\mathrm{v}=350 \mathrm{~m} / \mathrm{s}$
For one sided closed pipe:
Frequency, $v_{\mathrm{n}}=\dfrac{(2 \mathrm{n}-1) \mathrm{v}}{4 \mathrm{~L}} \quad$ where $\mathrm{n}=1,2,3$
When length of the pipe is $25 \mathrm{~cm}$ OR $0.25 \mathrm{~m}, \quad 1750=\dfrac{(2 \mathrm{n}-1) 350}{4 \times 0.25}$
$\text{n}=3$
Now let the length of the pipe after raising be $\mathrm{Lm}$.
For minimum increase in length of air column, $\mathrm{n}=3+1=4$
For minimum increase in length of air column, $\mathrm{n}=3+1=4$
$1750=\dfrac{(2\times 4-1)350}{4\times \text{L}}$
gives $\mathrm{L}=0.35 \mathrm{~m}$
Thus, the distance by which the pipe is raised $=0.35-0.25=0.1~\text{m}$
The distance by which the pipe is raised $=0.35-0.25=0.1 \mathrm{~m}=10 \mathrm{~cm}$
So,the Correct option is (D) .
Note:
Resonance describes the increased amplitude phenomenon that occurs when a periodically applied force is frequently applied. In a resonance column apparatus, air column vibrations can be set up. The condition for resonance is this. This occurs only when the air column length is proportional to one-fourth of the sound wavelength of sound waves that have a frequency equal to the tuning fork frequency.
Recently Updated Pages
Which will be the least stable resonating structure class 11 chemistry CBSE

How many 5 digit telephone numbers can be construc-class-11-maths-CBSE

How do you find the angle of the resultant vector class 11 physics CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is the need and importance of classification class 11 biology CBSE

Trending doubts
Difference between physical and chemical change class 11 chemistry CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Draw a labelled diagram of the neuron and describe class 11 biology CBSE

Draw a molecular orbital diagram of N2 or O2 with magnetic class 11 chemistry CBSE

Show that total energy of a freely falling body remains class 11 physics CBSE

Derive an expression for maximum height and range of class 11 physics CBSE

