A person is talking in a small room and the sound intensity level is 60 dB everywhere in the room. If eight people are talking simultaneously in the room, what is the sound intensity level?
A. 60 dB
B. 69 dB
C. 74 dB
D. 81 dB
Answer
629.1k+ views
Hint: First find the intensity of the eight person and then use the formula of finding the change in the intensity level, which helps in finding the required result.
$ \Rightarrow {B_2} - {B_1} = 10\log \left( {\dfrac{{{I_8}}}{I}} \right)$
Complete step by step solution:
Let ${B_1}$and${B_2}$is the initial intensity when 1 person is talking and intensity after 8 persons talking simultaneously respectively.
It is given that the person is talking in a small room and the sound intensity level$\left( {{B_1}} \right)$ is $60$ dB everywhere in the room.
Let $I$ be the initial intensity due to 1 person,
Therefore, the intensity due to 8 persons$\left( {{I_8}} \right)$ $ = 8I$
Change in the sound intensity level is given using the formula:
$ \Rightarrow {B_2} - {B_1} = 10\log \left( {\dfrac{{{I_8}}}{I}} \right)$
Substitute 60 as the value of${B_1}$, $8I$ as the value of ${I_8}$ in the above formula:
$ \Rightarrow {B_2} - 60 = 10\log \left( {\dfrac{{8I}}{I}} \right)$
$ \Rightarrow {B_2} - 60 = 10\log \left( 8 \right)$
8 can also expressed as${2^3}$ :
$ \Rightarrow {B_2} - 60 = 10\log \left( {{2^3}} \right)$
$ \Rightarrow {B_2} - 60 = 10\log \left( {{2^3}} \right)$
We know that:
$\log \left( {{a^b}} \right) = b\log a$
After applying the above relation, we have
$ \Rightarrow {B_2} - 60 = 10 \times 3\log 2$
The value of $\log 2 \approx 0.3$, so
$ \Rightarrow {B_2} - 60 = 10 \times 3 \times 0.3$
$ \Rightarrow {B_2} - 60 = 10 \times 0.9$
$ \Rightarrow {B_2} - 60 = 9$
$ \Rightarrow {B_2} = 9 + 60$
$ \Rightarrow {B_2} = 69$ dB
We have found the value of the ${B_2} = 69$dB. It means that, when 8 people are talking simultaneously in a small room, then the intensity level is $69$dB everywhere in the room.
Therefore, the option $\left( B \right)$ is correct.
Note: Remember that if the initial intensity of one person is $I$, then the intensity of eight persons is eight times the intensity of one person. That is, the intensity of eight-person is $8I$.
$ \Rightarrow {B_2} - {B_1} = 10\log \left( {\dfrac{{{I_8}}}{I}} \right)$
Complete step by step solution:
Let ${B_1}$and${B_2}$is the initial intensity when 1 person is talking and intensity after 8 persons talking simultaneously respectively.
It is given that the person is talking in a small room and the sound intensity level$\left( {{B_1}} \right)$ is $60$ dB everywhere in the room.
Let $I$ be the initial intensity due to 1 person,
Therefore, the intensity due to 8 persons$\left( {{I_8}} \right)$ $ = 8I$
Change in the sound intensity level is given using the formula:
$ \Rightarrow {B_2} - {B_1} = 10\log \left( {\dfrac{{{I_8}}}{I}} \right)$
Substitute 60 as the value of${B_1}$, $8I$ as the value of ${I_8}$ in the above formula:
$ \Rightarrow {B_2} - 60 = 10\log \left( {\dfrac{{8I}}{I}} \right)$
$ \Rightarrow {B_2} - 60 = 10\log \left( 8 \right)$
8 can also expressed as${2^3}$ :
$ \Rightarrow {B_2} - 60 = 10\log \left( {{2^3}} \right)$
$ \Rightarrow {B_2} - 60 = 10\log \left( {{2^3}} \right)$
We know that:
$\log \left( {{a^b}} \right) = b\log a$
After applying the above relation, we have
$ \Rightarrow {B_2} - 60 = 10 \times 3\log 2$
The value of $\log 2 \approx 0.3$, so
$ \Rightarrow {B_2} - 60 = 10 \times 3 \times 0.3$
$ \Rightarrow {B_2} - 60 = 10 \times 0.9$
$ \Rightarrow {B_2} - 60 = 9$
$ \Rightarrow {B_2} = 9 + 60$
$ \Rightarrow {B_2} = 69$ dB
We have found the value of the ${B_2} = 69$dB. It means that, when 8 people are talking simultaneously in a small room, then the intensity level is $69$dB everywhere in the room.
Therefore, the option $\left( B \right)$ is correct.
Note: Remember that if the initial intensity of one person is $I$, then the intensity of eight persons is eight times the intensity of one person. That is, the intensity of eight-person is $8I$.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is the full form of POSCO class 10 social science CBSE

Define Potential, Developed, Stock and Reserved resources

The speaker of the Lok Sabha is elected by the APresident class 10 social science CBSE

Complete the sentence with the most appropriate word class 10 english CBSE

