Answer

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**Hint:**

For this question, first write the definition of perfect square and its properties.

Observe all the properties and try to find out which given numbers are at units place.

**Complete step by step solution:**

To solve this question, first we have to know what is a perfect square?

Perfect square- A perfect square is a number that can be made by squaring a whole number.

Here are some properties are perfect square:

If a number has $1\,or\,9$ in the units place then its square ends in $1$.

If a number has $2\,or\,8$ in the units place then its square ends in $4$.

If a number has $3\text{ or }7$ in the units place then its square ends in $9$.

When a number ends with zero, its square ends with double zeros.

If a number ends with an odd number of zeros then it is not a perfect square.

In perfect squares, the digits at the units place are always $0, 1, 4, 5, 9$. The numbers having $2, 3, 8, 7$ are its end place are not perfect squares.

By the property (ii) it is clear that if we have $2, 3, 8, 7$ at the unit place then the number is not a perfect square.

So that we have only one option C that has a digit $8$ and if $8$ is at unit place then the given number is not a perfect number.

**Hence option C is the correct one.**

**Note:**

In such types of problems, students should know the properties of perfect squares otherwise they will face problems. Prime number is the whole number which has only two factors.

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