Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# A part of monthly expenses of a family on milk is fixed which is Rs. 700 and remaining varies with quantity of milk taken extra at the rate of $Rs.{\text{ }}25{\text{ }}per{\text{ }}litre$. Taking the quantity of milk required extra as $x$ litre and total expenditure on milk Rs. $y$, write a linear equation representing the above information.

Last updated date: 11th Aug 2024
Total views: 430.5k
Views today: 7.30k
Verified
430.5k+ views
Hint:Here, we have to form linear equation based on given information in the question , that the variables with power of 1 the variables provided are quantity of milk required extra as ‘$x$’ litre and total expenditure on milk Rs. ‘$y$’. Basically, it’s a question based on the formation of linear equations as per question. Also, a formula applied here is -
Remaining expenditure = (cost of milk per litre) $\times$(quantity of milk taken extra)

As per the question it is given that the quantity of milk required extra as ‘$x$’ litre and total expenditure on milk Rs. ‘$y$’.
Now, The Remaining expenditure = $= 25 \times$(quantity of milk taken extra)
$= 25 \times x = 25x$
Now the total expenditure y $= 700 + 25x$
$\Rightarrow y = 700 + 25x$
So the required linear equation which represents the above information is $y = 700 + 25x$