Question

A pair of dice is thrown. Find the probability of getting the sum 8 or more if 4 appears on the second dice:

Answer 1

Hint: We have to make the sum of two numbers that we get from the pair of dice 8 or more and one is already 4, so we will find the number from 1 – 6 that gives value 8 or more when added with 4. Then we will find the probability.

Complete step-by-step answer:
First we know that a dice contains numbers from 1 to 6, and we need to find all the numbers that are added with 4 will give the value 8 or more.
4 + 4 = 8
Hence, from this any number on the dice which is greater than or equal to 4 will be the required numbers.
Therefore, the numbers that will satisfy the above condition are: 4, 5, 6.
Hence there are three numbers from the six numbers so the probability will be: $\dfrac{3}{6}=\dfrac{1}{2}$
Hence the correct answer will be $\dfrac{1}{2}$ .

Note: In this question students might get confused that there are two dice but the role of one dice is just eliminate some options from the other dice so, in the end it has been converted to a simple question where we just need to find the probability of getting a number greater than or equal to 4 when a dice is rolled.