Question

A painting is painted on a cupboard 8cm long and 5cm wide such that there is a margin of 1.5 along each of its sides. Find the total area of margin.

Answer 1

Hint: Use the diagram to solve the question and for a better understanding of the question. We have the sides given in the question add the margin on the given side for finding the new side of the new rectangle.

Complete step by step answer:
We have given in the question
Cupboard length = 8cm
Cuboard breadth = 5cm
There is a margin of 1.5cm along each side of its sides.

Length of the smaller rectangle = length of a larger rectangle – $2 \times 1 \cdot 5$
Length of the smaller rectangle$ = 8 – 3$
$=5cm$
The breadth of the smaller rectangle = breadth of a larger rectangle $ - 2 \times 1 \cdot 5$
The breadth of the smaller rectangle $= 5 – 3 $
$=2cm$
Area of the margin = area of the larger rectangle – an area of the smaller rectangle
First, we have to find the area of the larger rectangle
Area of the larger rectangle = length $ \times $ breadth
Put the values
$= 8cm \times 5cm$
$=40c{m^2}$
Area of the smaller rectangle = length $ \times $ breadth
Area of the smaller rectangle $= 5cm \times 2cm$
$=10c{m^2}$
Area of the margin = area of the larger rectangle – an area of the smaller rectangle
Now put the values
Area of the margin = $40c{m^2}$- $10c{m^2}$
Area of the margin = $30c{m^2}$

Hence the total area of the margin is $30c{m^2}$.

Note:
Here students get confused between the side of the smaller rectangle they just add the 1.5cm in the side of the larger rectangle.convert the measuring unit in the same for all the solution.