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A number consists of two digits whose sum is 9. If 27 is subtracted from the number its digits are reversed. Find the number.

Answer
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Hint: Here, we will first consider the two digits of the number as x and y. Then, we will try to form equations using the given conditions to obtain the values of x and y and hence, we can find the number.

Complete Step-by-Step solution:
We know that if the digits of a two digit number are known then we can easily find the number.
If the first digit of the two digit number is x and the second digit is y, then we can write the given number as 10x+y .
Since, it is given that the sum of the digits of the number is 9. So, we can write the following equation:
x+y=9...........(1)
It is also given that if we subtract 27 from the number, its digit gets reversed. The reversed number will have now y as its first digit and x as its second digit.
So, the number formed after reversing the digits can be written as 10y+x .
So, on subtracting 27 from the given number and then equating it to its reverse, we get:
10x+y27=10y+x10x+y10yx=279x9y=279(xy)=27xy=279=3
Therefore, we have another equation as:
xy=3..........(2)
On adding equation (1) and equation (2), we get:
x+y+xy=9+32x=12x=122=6
So, the value of x comes out to be = 6.
On substituting x = 6 in equation (1), we get:
6+y=9y=96=3
So, the value of y is =3.
Since, the number is of the form of 10x+y, we can write that the number is :
=10×6+3=60+3=63
Hence, the required number is 63.

Note: Students should keep in mind that a two digit number is always represented in the form of 10x+y, where x and y are the first and second digits of the number respectively. It is not necessary to find the value of y using equation (1), it can also be found by using equation (2) also.
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