Question

A motorcyclist starts from rest and reaches a speed of $ 6m/s $ after travelling with uniform acceleration for $ 3s $ . What is his acceleration?

Answer 1

Hint: Motion is the state of an object's change in position over time. It is defined in terms of displacement, distance, speed, acceleration, time and velocity. Examples of motion include running, movement of cars, flowing of water etc. This is a basic question which can be solved with the help of equations of motion.

Formula Used
We will use the following equation of motion to solve this question:
 $ v = u + at $
Where
 $ v $ is the final velocity
 $ u $ is the initial velocity
 $ a $ is the acceleration of the body
 $ t $ is the time taken.

Complete step by step answer:
According to the question, we have the following information
Initial velocity, $ u = 0m/s $
Final velocity, $ v = 3s $
Time taken, $ t = 3s $
We will use the following equation of motion
 $ v = u + at $
The above equation can also be written as
 $ \Rightarrow a = \dfrac{{v - u}}{t} $
 $ \Rightarrow a = \dfrac{{6 - 0}}{3} $
Therefore we get, $ \therefore a = 2m/{s^2} $ .

Note:
The equation used above only speaks of the acceleration, time, initial and final velocity. Let's assume a body which has $ m $ mass and $ u $ initial velocity. Let its final velocity become $ v = u + at $ after time $ t $ due to uniform acceleration $ a $ . Then we will use $ v = u + at $ to solve such questions.
There are three equations of motion in the event of uniform acceleration, which are also known as the laws of constant acceleration. Therefore, components such as displacement ( $ s $ ), velocity (initial and final), time ( $ t $ ) and acceleration ( $ a $ ) are derived from these equations. They can therefore only be used if the acceleration is constant and the motion is a straight line.