A metal oxide contains 20% oxygen by weight. Find the equivalent weight.
Answer
589.8k+ views
Hint: An oxide is a chemical compound which contains at least one oxygen atom with any another element. Oxide is an anion of oxygen represented as ${{O}^{2-}}$ .In this state the oxygen is present in -2 oxidation state and acts as an anion which carries negative charge.
Complete answer:
Equivalent weight which is also known by the name gram equivalent is defined as the mass of one equivalent which can be simplified in a manner that mass of a given substance which will combine with or we can also explain it which will displace a fixed quantity of another substance. The equivalent weight of an element can be defined as the mass which combines with or displaces 1.008 gram of hydrogen or 8.0 grams of oxygen or 35.5 grams of chlorine. These values correspond to the atomic weight which is divided by its valency.
Now we know that equivalent weight is that which combines with 8 parts by weight of oxygen.
If 20% mass is of oxygen which is given then remaining 80% mass is contributed by the metal,
Then the equivalent weight of metal can be calculated by $\dfrac{80}{20}\times 8=32$
Hence a metal oxide which contains 20% oxygen by weight then its equivalent weight will be 32 g.
Note:
Oxides can be formed due to the electronegative nature of oxygen which forms stable chemical bonds with almost all metals and they give corresponding oxides of that metal. Ratio of metal oxide tells us about how many metals and oxygen atoms are connected with each other.
Complete answer:
Equivalent weight which is also known by the name gram equivalent is defined as the mass of one equivalent which can be simplified in a manner that mass of a given substance which will combine with or we can also explain it which will displace a fixed quantity of another substance. The equivalent weight of an element can be defined as the mass which combines with or displaces 1.008 gram of hydrogen or 8.0 grams of oxygen or 35.5 grams of chlorine. These values correspond to the atomic weight which is divided by its valency.
Now we know that equivalent weight is that which combines with 8 parts by weight of oxygen.
If 20% mass is of oxygen which is given then remaining 80% mass is contributed by the metal,
Then the equivalent weight of metal can be calculated by $\dfrac{80}{20}\times 8=32$
Hence a metal oxide which contains 20% oxygen by weight then its equivalent weight will be 32 g.
Note:
Oxides can be formed due to the electronegative nature of oxygen which forms stable chemical bonds with almost all metals and they give corresponding oxides of that metal. Ratio of metal oxide tells us about how many metals and oxygen atoms are connected with each other.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

