
A mass $M$ is suspended by a rope from a rigid support $P$ as shown in figure. Another rope is tied at the end Q and it is pulled horizontally with a force $F$. If the rope PQ makes an angle $\theta $ with the vertical in equilibrium, then the tension in the string PQ is
A. $\dfrac{F}{{\sin \theta }}$
B. $F\sin \theta $
C. $F\cos \theta $
D. $\dfrac{F}{{\cos \theta }}$
Answer
491.1k+ views
Hint: It is given that a mass m is suspended from a rigid support P. A force is applied towards the point Q. It is said that the system is in equilibrium and PQ makes an angle $\theta $ with vertical. We have to find the tension in the string PQ. Draw a free body diagram.
Complete step by step answer:
It is given that a mass $m$ is suspended from a rigid support P. A force is applied towards the point Q. It is said that the system is in equilibrium and PQ makes an angle $\theta $ with vertical. We have to find the tension in the string PQ.
By taking the vertical component at point Q. $mg$ acts upwards at the point Q.Therefore,
$T\cos \theta = F$
$\Rightarrow T = \dfrac{F}{{\cos \theta }}$
Taking the horizontal component,
$T\sin \theta = F$
$\therefore T = \dfrac{F}{{\sin \theta }}$
Then the tension in the string PQ is $\dfrac{F}{{\sin \theta }}$.
Therefore, the correct answer is option A.
Additional information: In physics, the pulling force is generally applied by using a string, link, chain, or any similar one-dimensional continuous item, or by each end of a bar, bracket part, or comparable three-dimensional article is called tension.According to the principle of equilibrium, A body is said to be in equilibrium if the algebraic sum of all forces acting on the body is zero, and also if the algebraic sum of moments of forces about any fixed point is zero.
A body is said to be in equilibrium if there is no translation and no rotation of the body under the application of external forces. Sometimes the resultant of the force system is not equal to zero. That means the body is not in equilibrium. The force which is required to keep the body in equilibrium, is known as equilibrant.
A free-body diagram is the diagram which represents the various forces acting on the body.
Tension in a string is always along the string and away from the object . In an ideal string tension at all points of the string will be the same. In a string or in a chain tension is only extensional. In a rod, tension can be extensional or compressional. Net force acting on an ideal string(massless) is always zero.
Note: To solve this question one should know the concept of equilibrium of forces.The students should deeply understand the question and the figure carefully and implement the formulas at the correct places.
Complete step by step answer:
It is given that a mass $m$ is suspended from a rigid support P. A force is applied towards the point Q. It is said that the system is in equilibrium and PQ makes an angle $\theta $ with vertical. We have to find the tension in the string PQ.
By taking the vertical component at point Q. $mg$ acts upwards at the point Q.Therefore,
$T\cos \theta = F$
$\Rightarrow T = \dfrac{F}{{\cos \theta }}$
Taking the horizontal component,
$T\sin \theta = F$
$\therefore T = \dfrac{F}{{\sin \theta }}$
Then the tension in the string PQ is $\dfrac{F}{{\sin \theta }}$.
Therefore, the correct answer is option A.
Additional information: In physics, the pulling force is generally applied by using a string, link, chain, or any similar one-dimensional continuous item, or by each end of a bar, bracket part, or comparable three-dimensional article is called tension.According to the principle of equilibrium, A body is said to be in equilibrium if the algebraic sum of all forces acting on the body is zero, and also if the algebraic sum of moments of forces about any fixed point is zero.
A body is said to be in equilibrium if there is no translation and no rotation of the body under the application of external forces. Sometimes the resultant of the force system is not equal to zero. That means the body is not in equilibrium. The force which is required to keep the body in equilibrium, is known as equilibrant.
A free-body diagram is the diagram which represents the various forces acting on the body.
Tension in a string is always along the string and away from the object . In an ideal string tension at all points of the string will be the same. In a string or in a chain tension is only extensional. In a rod, tension can be extensional or compressional. Net force acting on an ideal string(massless) is always zero.
Note: To solve this question one should know the concept of equilibrium of forces.The students should deeply understand the question and the figure carefully and implement the formulas at the correct places.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Why is steel more elastic than rubber class 11 physics CBSE

What is boron A Nonmetal B Metal C Metalloid D All class 11 chemistry CBSE

What is Environment class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

How many squares are there in a chess board A 1296 class 11 maths CBSE

