Answer
Verified
394.8k+ views
Hint: The concept of successive profit will be applied in this question. Let the cost price for the manufacturer be $p$. For Wholesale dealers, it will become $p + 18\% p$. For retailers it will become $p + 18\% p + 20\% (p + 18\% p)$. Further, it is given that the profit earned by the retailer is 25% when the selling price is Rs.30.09. We will apply the formula of profit i.e., $p\% = \dfrac{{S.P - C.P}}{{C.P}} \times 100$, where S.P is selling price and C.P is cost price.
Complete step-by-step answer:
Let the cost price for manufacturer be $p$
As, mentioned in question the manufacture sells it at a profit of 18%
Therefore, the cost price for whole seller is $p + 18\% p$
$ = p + \dfrac{{18}}{{100}}p = \dfrac{{118}}{{100}}p$
Now, the wholesaler sells it at a profit of 20%.
Therefore, the cost price for Retailer is $p + 18\% p + 20\% (p + 18\% p)$
$
= \dfrac{{118}}{{100}}p + \dfrac{{20}}{{100}} \times \dfrac{{118}}{{100}}p \\
= \dfrac{{345}}{{250}}p \\
$
Now, the retailer sells it at a profit of 25%.
Therefore, the selling price for retailer is
$
\dfrac{{345}}{{250}}p + \dfrac{{25}}{{100}} \times \dfrac{{345}}{{250}}p \\
= \dfrac{{805}}{{500}}p \\
$
The selling price given in the question is Rs.30.09
$
\Rightarrow \dfrac{{805}}{{500}}p = 30.09 \\
\Rightarrow p = 17 \\
$
Hence, The Cost Price for the manufacturer is Rs.17
So, the correct answer is “Option C”.
Note: Important aspect to notice and keep in mind is that the cost price for the one becomes the selling price for the other. As in this question, the selling price of the manufacturer becomes the cost price of the wholesaler. Further, the selling price of the whole seller becomes the cost price of the retailer. The shortcut way to do this problem and finding the cost price, say P is
$p = \dfrac{{100}}{{100 + {p_1}}} \times \dfrac{{100}}{{100 + {p_2}}} \times \dfrac{{100}}{{100 + {p_3}}} \times s.p$, where ${p_1},{p_2}$ and ${p_3}$ are the profits given and $s.p$ is the selling price. Putting ${p_1} = 18,{p_2} = 20$,${P_3} = 25$ and $s.p = 30.09$.
$
\Rightarrow P = \dfrac{{100}}{{118}} \times \dfrac{{100}}{{120}} \times \dfrac{{100}}{{125}} \times 30.09 \\
\Rightarrow P = 17 \\
$
Complete step-by-step answer:
Let the cost price for manufacturer be $p$
As, mentioned in question the manufacture sells it at a profit of 18%
Therefore, the cost price for whole seller is $p + 18\% p$
$ = p + \dfrac{{18}}{{100}}p = \dfrac{{118}}{{100}}p$
Now, the wholesaler sells it at a profit of 20%.
Therefore, the cost price for Retailer is $p + 18\% p + 20\% (p + 18\% p)$
$
= \dfrac{{118}}{{100}}p + \dfrac{{20}}{{100}} \times \dfrac{{118}}{{100}}p \\
= \dfrac{{345}}{{250}}p \\
$
Now, the retailer sells it at a profit of 25%.
Therefore, the selling price for retailer is
$
\dfrac{{345}}{{250}}p + \dfrac{{25}}{{100}} \times \dfrac{{345}}{{250}}p \\
= \dfrac{{805}}{{500}}p \\
$
The selling price given in the question is Rs.30.09
$
\Rightarrow \dfrac{{805}}{{500}}p = 30.09 \\
\Rightarrow p = 17 \\
$
Hence, The Cost Price for the manufacturer is Rs.17
So, the correct answer is “Option C”.
Note: Important aspect to notice and keep in mind is that the cost price for the one becomes the selling price for the other. As in this question, the selling price of the manufacturer becomes the cost price of the wholesaler. Further, the selling price of the whole seller becomes the cost price of the retailer. The shortcut way to do this problem and finding the cost price, say P is
$p = \dfrac{{100}}{{100 + {p_1}}} \times \dfrac{{100}}{{100 + {p_2}}} \times \dfrac{{100}}{{100 + {p_3}}} \times s.p$, where ${p_1},{p_2}$ and ${p_3}$ are the profits given and $s.p$ is the selling price. Putting ${p_1} = 18,{p_2} = 20$,${P_3} = 25$ and $s.p = 30.09$.
$
\Rightarrow P = \dfrac{{100}}{{118}} \times \dfrac{{100}}{{120}} \times \dfrac{{100}}{{125}} \times 30.09 \\
\Rightarrow P = 17 \\
$
Recently Updated Pages
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Find the values of other five trigonometric functions class 10 maths CBSE
Trending doubts
State the differences between manure and fertilize class 8 biology CBSE
Why are xylem and phloem called complex tissues aBoth class 11 biology CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
What would happen if plasma membrane ruptures or breaks class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What precautions do you take while observing the nucleus class 11 biology CBSE
What would happen to the life of a cell if there was class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE