Question

A man purchases an electric heater whose printed price is Rs. 160. If he received two successive discounts of 20% and 10%, he paid _____
A) Rs. 112
B) Rs. 129.60
C) Rs. 119.60
D) Rs. 115.20

Answer 1

Hint: This question is from the topic of profit, loss and discount. In this question, we have to find out the final payment made by the man. In solving this question, we will first find out the final price 1 after the discount of 20%. After that, we will find out the final price 2 after putting the discount of 10%. After that, we will get our answer.

Complete step by step solution:
Let us solve this question.
In this question, we have given that the printing price of electric heater is Rs. 160. And, there are two successive discounts on that electric heater that is 20% and 10%. So, we have to find the final price of the heater by putting those successive discounts.
Let us first find out the final price of the heater after having a discount of 20%.
Final price 1 = \[160-\dfrac{20}{100}\times 160=160-32=128\]
So, final price 1 = Rs. 128
Similarly, we will offer a discount of 10% on Rs. 128.
Hence, final price 2 = \[128-\dfrac{10}{100}\times 128=128-12.8=115.2\]
So, final price 2 = Rs. 115.20

So, the correct answer is “Option D”.

Note: We should have a better knowledge in the topic profit, loss and discounts to solve this type of question easily. We can solve this question by different method.
The money paid by the man for the heater will be
((160-20%)-10%)
We can write the above as
\[\left( \left( 160-\dfrac{20}{100}\times 160 \right)-10\% \right)\]
\[\Rightarrow \left( \left( 160-32 \right)-10\% \right)\]
\[\Rightarrow \left( 128-10\% \right)\]
\[\Rightarrow \left( 128-\dfrac{10}{100}\times 128 \right)\]
\[\Rightarrow \left( 128-0.1\times 128 \right)\]
\[\Rightarrow \left( 128-12.8 \right)\]
\[\Rightarrow \left( 115.20 \right)\]
Hence, money paid is Rs. 115.20