
A man has three friends. The number of ways he can invite one friend every day for dinner on six successive nights so that no friend is invited more than three times is
(a) 640
(b) 320
(c) 420
(d) 510
Answer
514.8k+ views
Hint: The possible situations are 3 for which the conditions satisfy. For the 1st given situation one often will be invited for three days, in between remaining 2 one of them will be invited for 2 days and the other for remaining 1 day. Now, for the 2nd situation all are invited for 2 days each. And in the last situation any two of the three will be invited for 3 days each. Then find the ways of all the situations hence, add them all.
Complete step-by-step answer:
In the question, we are told that a man has three friends. Now we have to find the number of ways to invite one friend everyday for dinner on six successive nights so that no friend is invited more than three times.
After observing the question and analyzing the situation we get that there are three different possible situations where three possible can be invited such that no one is invited more than three times.
So, let’s go for 1st situation, one of the three will be invited once, in between rest of two anyone will be invited twice and last will be invited thrice.
Anybody among three can be invited in 3! or 6 ways.
So, the person coming for three days can be chosen in ways. So, there are 3.
The person coming for two days can be chosen in ways. And the last one will come on the left 1 day.
Hence, the total number of ways is . Now as we know that is equal to so we can calculate it as,
ways
Now let’s go to the 2nd situation where all the friends were invited two days each.
All are invited in 1 way.
So, the person coming for two days can be chosen in ways. So, there are 4. The person coming for two days can be chosen in ways. And the last one will come on the left 2 days.
As the distribution is the same, we will divide by 3! As total persons are three, we will multiply it by 3.
Hence the total number of ways is . Now as we know that is equal to so we can calculate it as,
ways
Now, let’s go to the last situation where only 2 of the 3 were invited on three days each.
So now choosing 2 friends from 3 friends, it can be done in or 3 ways.
So, the person coming for three days can be chosen in ways. So, now left days are 3.
And the last one will come on the left days in ways.
Hence, the total number of ways is . Now as we know that is equal to so we can calculate it as,
ways
So, the total number of ways is 360+90+60 ways or 510 ways.
So, the correct option is ‘d’.
Note: Students can also do the question by finding all possible ways and then subtracting those cases which does not satisfy the situation given in the question.
Complete step-by-step answer:
In the question, we are told that a man has three friends. Now we have to find the number of ways to invite one friend everyday for dinner on six successive nights so that no friend is invited more than three times.
After observing the question and analyzing the situation we get that there are three different possible situations where three possible can be invited such that no one is invited more than three times.
So, let’s go for 1st situation, one of the three will be invited once, in between rest of two anyone will be invited twice and last will be invited thrice.
Anybody among three can be invited in 3! or 6 ways.
So, the person coming for three days can be chosen in
The person coming for two days can be chosen in
Hence, the total number of ways is
Now let’s go to the 2nd situation where all the friends were invited two days each.
All are invited in 1 way.
So, the person coming for two days can be chosen in
As the distribution is the same, we will divide by 3! As total persons are three, we will multiply it by 3.
Hence the total number of ways is
Now, let’s go to the last situation where only 2 of the 3 were invited on three days each.
So now choosing 2 friends from 3 friends, it can be done in
So, the person coming for three days can be chosen in
And the last one will come on the left days in
Hence, the total number of ways is
So, the total number of ways is 360+90+60 ways or 510 ways.
So, the correct option is ‘d’.
Note: Students can also do the question by finding all possible ways and then subtracting those cases which does not satisfy the situation given in the question.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Express the following as a fraction and simplify a class 7 maths CBSE

The length and width of a rectangle are in ratio of class 7 maths CBSE

The ratio of the income to the expenditure of a family class 7 maths CBSE

How do you write 025 million in scientific notatio class 7 maths CBSE

How do you convert 295 meters per second to kilometers class 7 maths CBSE

Write the following in Roman numerals 25819 class 7 maths CBSE

Trending doubts
Give 10 examples of unisexual and bisexual flowers

Draw a labelled sketch of the human eye class 12 physics CBSE

Franz thinks Will they make them sing in German even class 12 english CBSE

Draw a diagram of a flower and name the parts class 12 biology ICSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

The speed of light will be minimum while passing through class 12 physics CBSE
