
A man bought a horse and a carriage for 3000. He sold the horse at a gain of 20% and the carriage at a loss of 10%, thereby gaining 2% on the whole. Find the cost of the horse.
A. 1000
B. 1200
C. 1500
D. 1650
Answer
588.3k+ views
Hint:- We can assume the cost of horse as variable x and then we can find the total selling cost of horse and carriage and on comparing that with the 3000 + 2% of 3000 we will get the value of x.
Complete step-by-step answer:
Let the cost of horse will be Rs. x
So, the cost of the carriage will be Rs. (3000 – x).
Now as we know that horse is sold at the 20% gain.
So, we can find the gain amount by using the percentage formula.
As we know that according to percentage formula B% of A will be \[\dfrac{B}{{100}} \times A\]
So, the 20% of the cost of horse (i.e. x) will be \[\dfrac{{20}}{{100}} \times x = \dfrac{x}{5}\]
So, the horse will be sold by the man at a price of x + \[\dfrac{x}{5}\] = Rs. \[\dfrac{{6x}}{5}\]
Now, we had to find the selling price of carriage.
So, the 10% of the cost of carriage (i.e. 3000 – x) will be \[\dfrac{{10}}{{100}} \times \left( {3000 - x} \right) = \dfrac{{\left( {3000 - x} \right)}}{{10}}\]
Now as the man sold the carriage at the loss of 10%.
So, the selling price of carriage will be (3000 – x) – \[\dfrac{{\left( {3000 - x} \right)}}{{10}}\] = \[\dfrac{{9\left( {3000 - x} \right)}}{{10}}\]
So, the total cost of selling horse and carriage will be \[\dfrac{{6x}}{5} + \dfrac{{9\left( {3000 - x} \right)}}{{10}} = \dfrac{{12x + 27000 - 9x}}{{10}} = \dfrac{{3x + 27000}}{{10}}\] (1)
Now as it is given that the man gains 2% on the whole price.
So, 2% of 3000 will be \[\dfrac{2}{{100}} \times 3000 = 60\]
So, the total selling price will be Rs (3000 + 60) = Rs. 3060
So, now equating equation 1 with 3060.
\[\dfrac{{3x + 27000}}{{10}}\] = 3060
Cross-multiplying above equation.
3x + 27000 = 30600
Subtracting 27000 from both the sides of the above equation.
3x = 3600
Dividing both sides of the above equation by 3.
x = 1200
So, the cost of the horse will be Rs. 1200.
Hence, the correct option will be B.
Note:- Whenever we come up with this type of then there is also an alternate method to find the selling price directly like if the cost of any article is A and it is sold at a gain percent of B% then the selling price of the article will be \[\dfrac{{\left( {100 + B} \right)}}{{100}} \times A\], and if the article is sold at the loss percent of B% then the selling price of the article will be \[\dfrac{{\left( {100 - B} \right)}}{{100}} \times A\].
Complete step-by-step answer:
Let the cost of horse will be Rs. x
So, the cost of the carriage will be Rs. (3000 – x).
Now as we know that horse is sold at the 20% gain.
So, we can find the gain amount by using the percentage formula.
As we know that according to percentage formula B% of A will be \[\dfrac{B}{{100}} \times A\]
So, the 20% of the cost of horse (i.e. x) will be \[\dfrac{{20}}{{100}} \times x = \dfrac{x}{5}\]
So, the horse will be sold by the man at a price of x + \[\dfrac{x}{5}\] = Rs. \[\dfrac{{6x}}{5}\]
Now, we had to find the selling price of carriage.
So, the 10% of the cost of carriage (i.e. 3000 – x) will be \[\dfrac{{10}}{{100}} \times \left( {3000 - x} \right) = \dfrac{{\left( {3000 - x} \right)}}{{10}}\]
Now as the man sold the carriage at the loss of 10%.
So, the selling price of carriage will be (3000 – x) – \[\dfrac{{\left( {3000 - x} \right)}}{{10}}\] = \[\dfrac{{9\left( {3000 - x} \right)}}{{10}}\]
So, the total cost of selling horse and carriage will be \[\dfrac{{6x}}{5} + \dfrac{{9\left( {3000 - x} \right)}}{{10}} = \dfrac{{12x + 27000 - 9x}}{{10}} = \dfrac{{3x + 27000}}{{10}}\] (1)
Now as it is given that the man gains 2% on the whole price.
So, 2% of 3000 will be \[\dfrac{2}{{100}} \times 3000 = 60\]
So, the total selling price will be Rs (3000 + 60) = Rs. 3060
So, now equating equation 1 with 3060.
\[\dfrac{{3x + 27000}}{{10}}\] = 3060
Cross-multiplying above equation.
3x + 27000 = 30600
Subtracting 27000 from both the sides of the above equation.
3x = 3600
Dividing both sides of the above equation by 3.
x = 1200
So, the cost of the horse will be Rs. 1200.
Hence, the correct option will be B.
Note:- Whenever we come up with this type of then there is also an alternate method to find the selling price directly like if the cost of any article is A and it is sold at a gain percent of B% then the selling price of the article will be \[\dfrac{{\left( {100 + B} \right)}}{{100}} \times A\], and if the article is sold at the loss percent of B% then the selling price of the article will be \[\dfrac{{\left( {100 - B} \right)}}{{100}} \times A\].
Recently Updated Pages
Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write the 6 fundamental rights of India and explain in detail

Difference Between Plant Cell and Animal Cell

What is pollution? How many types of pollution? Define it

What is the Full Form of ISI and RAW

