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A loading tempo can carry \[482\] boxes of biscuits weighing $15kg$ each, whereas a van can carry $518$ boxes each of the same weight. Find the total weight that can be carried by both the vehicles.

Answer
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Hint: Weight of each box and number of boxes is given for the tempo and van. Multiplying we get the total weight carried by each vehicle. Then adding the two values gives the total weight.

Formula used:
If the weight of an object is ${\text{x kg}}$, weight of $n$ objects is ${\text{nx kg}}$.

Complete step-by-step answer:
It is given that the tempo can carry \[482\] boxes of biscuits weighing $15kg$ each and the van can carry $518$ boxes of biscuits weighing $15kg$.
We are asked to find the total weight that can be carried by both the vehicles.
Total weight will be equal to the sum of weights that can be carried by tempo and van individually.
If the weight of an object is ${\text{x kg}}$, the weight of $n$ objects is ${\text{nx kg}}$.
So, the weight that can be carried by the tempo ${W_T} = {\text{number of boxes in tempo}} \times {\text{weight of one box}}$
Substituting we get, ${W_T} = 482 \times 15$
Also, the weight that can be carried by the tempo ${W_V} = {\text{number of boxes in van}} \times {\text{weight of one box}}$
Substituting we get, ${W_C} = 518 \times 15$
Now, total weight $W = {W_T} + {W_V}$
$ \Rightarrow W = 482 \times 15 + 518 \times 15$
Taking $15$ as common we get,
$ \Rightarrow W = (482 + 518) \times 15$
$ \Rightarrow W = 1000 \times 15 = 15000$
So, the total weight that can be carried by both the vehicles is $15000kg$.
$\therefore $ The answer is $15000kg$.

Note: Since boxes were of the same weight we can simply multiply it with the total number of boxes of both tempo and van. If the boxes in tempo and van were of different weight, we have to multiply them separately and then add up to get the total weight that can be carried. Anyway the weight of a certain number of objects is equal to the product of the number of objects and their individual weight.
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