
A line AB in three dimensional space making an angle ${45^\circ }$ and ${120^\circ }$ with the positive x-axis and the positive y-axis respectively . If AB makes an acute angle e with the positive z-axis , then e equals to :
A) ${45^\circ }$
B) ${60^\circ }$
C) ${75^\circ }$
D) ${30^\circ }$
Answer
585.9k+ views
Hint: As we know that if the line AB makes an angle (a , b ,c ) with the positive (x , y , z) axis then ${\cos ^2}a + {\cos ^2}b + {\cos ^2}c = 1$ hence in this question two angles are know third one is find out from this formula .
Complete step-by-step answer:
In the question it is given that Line AB is in three dimensional making angles ${45^\circ }$ and ${120^\circ }$ with the positive x-axis and the positive y-axis respectively .
And makes an acute angle e with the positive z-axis mean that angle e < ${90^\circ }$ .
Hence from the Vector property we know that if the line AB makes an angle (a , b ,c ) with the positive (x , y , z) axis then ${\cos ^2}a + {\cos ^2}b + {\cos ^2}c = 1$ .
Hence from the question a = ${45^\circ }$ , b = ${120^\circ }$and c = e ,
${\cos ^2}{45^\circ } + {\cos ^2}{120^\circ } + {\cos ^2}e = 1$
${\cos ^2}e = 1 - ({\cos ^2}{45^\circ } + {\cos ^2}{120^\circ })$
${\cos ^2}e = 1 - {\left( {\dfrac{1}{{\sqrt 2 }}} \right)^2} - {\left( {\dfrac{{ - 1}}{2}} \right)^2}$
${\cos ^2}e = 1 - \left( {\dfrac{1}{2}} \right) - \left( {\dfrac{1}{4}} \right)$
${\cos ^2}e = 1 - \left( {\dfrac{3}{4}} \right)$
${\cos ^2}e = \left( {\dfrac{1}{4}} \right)$
$\cos e = \pm \left( {\dfrac{1}{2}} \right)$
For the acute angle e < ${90^\circ }$ hence only positive will be considered .
$\cos e = \left( {\dfrac{1}{2}} \right)$
e = ${60^\circ }$
Hence option B will be the correct answer.
Note: In this question it is given in that the angle is e is acute angle , If it is obtuse angle then we have to consider the negative value of $\cos e$that is $\cos e = - \left( {\dfrac{1}{2}} \right)$ Hence the $e = {120^\circ }$ .
Multiplication of a vector by a scalar quantity is called Scaling. In this type of multiplication, only the magnitude of a vector is changed not the direction.
Always remember that if a line makes an angle (a , b ,c ) with the positive (x , y , z) axis then ${\cos ^2}a + {\cos ^2}b + {\cos ^2}c = 1$ .
Complete step-by-step answer:
In the question it is given that Line AB is in three dimensional making angles ${45^\circ }$ and ${120^\circ }$ with the positive x-axis and the positive y-axis respectively .
And makes an acute angle e with the positive z-axis mean that angle e < ${90^\circ }$ .
Hence from the Vector property we know that if the line AB makes an angle (a , b ,c ) with the positive (x , y , z) axis then ${\cos ^2}a + {\cos ^2}b + {\cos ^2}c = 1$ .
Hence from the question a = ${45^\circ }$ , b = ${120^\circ }$and c = e ,
${\cos ^2}{45^\circ } + {\cos ^2}{120^\circ } + {\cos ^2}e = 1$
${\cos ^2}e = 1 - ({\cos ^2}{45^\circ } + {\cos ^2}{120^\circ })$
${\cos ^2}e = 1 - {\left( {\dfrac{1}{{\sqrt 2 }}} \right)^2} - {\left( {\dfrac{{ - 1}}{2}} \right)^2}$
${\cos ^2}e = 1 - \left( {\dfrac{1}{2}} \right) - \left( {\dfrac{1}{4}} \right)$
${\cos ^2}e = 1 - \left( {\dfrac{3}{4}} \right)$
${\cos ^2}e = \left( {\dfrac{1}{4}} \right)$
$\cos e = \pm \left( {\dfrac{1}{2}} \right)$
For the acute angle e < ${90^\circ }$ hence only positive will be considered .
$\cos e = \left( {\dfrac{1}{2}} \right)$
e = ${60^\circ }$
Hence option B will be the correct answer.
Note: In this question it is given in that the angle is e is acute angle , If it is obtuse angle then we have to consider the negative value of $\cos e$that is $\cos e = - \left( {\dfrac{1}{2}} \right)$ Hence the $e = {120^\circ }$ .
Multiplication of a vector by a scalar quantity is called Scaling. In this type of multiplication, only the magnitude of a vector is changed not the direction.
Always remember that if a line makes an angle (a , b ,c ) with the positive (x , y , z) axis then ${\cos ^2}a + {\cos ^2}b + {\cos ^2}c = 1$ .
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Complete reduction of benzene diazonium chloride with class 12 chemistry CBSE

How can you identify optical isomers class 12 chemistry CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

